Mysql 复合外键插入

我有三个表格：

公司

，

案例

和

报告

公司：

CREATE TABLE IF NOT EXISTS `db`.`company` (
  `name` VARCHAR(50) NOT NULL,
  `password` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`name`))
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`case` (
  `id` VARCHAR(50) NOT NULL,
  `image` VARCHAR(255) NULL,
  `title` VARCHAR(100) NULL,
  `description` VARCHAR(255) NULL,
  `address` VARCHAR(255) NULL,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `company_name` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`company_name`, `id`),
  CONSTRAINT `fk_case_company`
    FOREIGN KEY (`company_name`)
    REFERENCES `db`.`company` (`name`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`report` (
  `type` VARCHAR(50) NULL,
  `image` VARCHAR(255) NULL,
  `description` VARCHAR(255) NULL,
  `approval` BINARY NULL DEFAULT 0,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `id` INT NOT NULL AUTO_INCREMENT,
  `case_company_name` VARCHAR(50) NOT NULL,
  `case_id` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`id`, `case_company_name`, `case_id`),
  INDEX `fk_report_case1_idx` (`case_company_name` ASC, `case_id` ASC),
  CONSTRAINT `fk_report_case1`
    FOREIGN KEY (`case_company_name` , `case_id`)
    REFERENCES `db`.`case` (`company_name` , `id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

案例：

CREATE TABLE IF NOT EXISTS `db`.`company` (
  `name` VARCHAR(50) NOT NULL,
  `password` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`name`))
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`case` (
  `id` VARCHAR(50) NOT NULL,
  `image` VARCHAR(255) NULL,
  `title` VARCHAR(100) NULL,
  `description` VARCHAR(255) NULL,
  `address` VARCHAR(255) NULL,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `company_name` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`company_name`, `id`),
  CONSTRAINT `fk_case_company`
    FOREIGN KEY (`company_name`)
    REFERENCES `db`.`company` (`name`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`report` (
  `type` VARCHAR(50) NULL,
  `image` VARCHAR(255) NULL,
  `description` VARCHAR(255) NULL,
  `approval` BINARY NULL DEFAULT 0,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `id` INT NOT NULL AUTO_INCREMENT,
  `case_company_name` VARCHAR(50) NOT NULL,
  `case_id` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`id`, `case_company_name`, `case_id`),
  INDEX `fk_report_case1_idx` (`case_company_name` ASC, `case_id` ASC),
  CONSTRAINT `fk_report_case1`
    FOREIGN KEY (`case_company_name` , `case_id`)
    REFERENCES `db`.`case` (`company_name` , `id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

报告：

CREATE TABLE IF NOT EXISTS `db`.`company` (
  `name` VARCHAR(50) NOT NULL,
  `password` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`name`))
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`case` (
  `id` VARCHAR(50) NOT NULL,
  `image` VARCHAR(255) NULL,
  `title` VARCHAR(100) NULL,
  `description` VARCHAR(255) NULL,
  `address` VARCHAR(255) NULL,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `company_name` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`company_name`, `id`),
  CONSTRAINT `fk_case_company`
    FOREIGN KEY (`company_name`)
    REFERENCES `db`.`company` (`name`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `db`.`report` (
  `type` VARCHAR(50) NULL,
  `image` VARCHAR(255) NULL,
  `description` VARCHAR(255) NULL,
  `approval` BINARY NULL DEFAULT 0,
  `date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `id` INT NOT NULL AUTO_INCREMENT,
  `case_company_name` VARCHAR(50) NOT NULL,
  `case_id` VARCHAR(50) NOT NULL,
  PRIMARY KEY (`id`, `case_company_name`, `case_id`),
  INDEX `fk_report_case1_idx` (`case_company_name` ASC, `case_id` ASC),
  CONSTRAINT `fk_report_case1`
    FOREIGN KEY (`case_company_name` , `case_id`)
    REFERENCES `db`.`case` (`company_name` , `id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

当我使用

phpMyAdmin

将一行插入

case

表时：

所以外键就像我想象的那样工作。但是，当我尝试在

报告

表中插入一行时，它使用了一个由两列组成的复合外键，它看起来如下所示：

---

为什么会这样？在我看来，这两个表之间似乎没有建立连接，

case\u company\u name

和

case\u id

只是常规列。

很可能这只意味着phpmyadmin不能以这种方式处理复合引用。 您可以使用

SHOW CREATE TABLE report