Mysql SQL查询使用order子句从两个单独的表中进行选择

我有两张桌子：

tickets
ticket_updates

我正在尝试运行一个查询，其中显示来自tickets表的数据和

ticket\u updates

表中最新的

datetime

SELECT * from tickets where status = 'Completed' order by ??? DESC LIMIT 0,50 

---

tickets

表中的

ticketnumber

与

ticket\u更新

表中的

ticketnumber

匹配一种方法是汇总

ticket\u更新

表以获得所需内容：

SELECT * from tickets where status = 'Completed' order by ??? DESC LIMIT 0,50 

select t.*
from tickets t join
     (select ticketid, max(datetime) as max_datetime
      from ticket_updates
      group by ticketid
     ) tu
     on t.ticketid = tu.max_datetime
order by tu.max_datetime desc
limit 0, 50;

---

试试这个。

连接两个表，然后按以下顺序排序：

SELECT a.*
from tickets a, ticket_updates b
where a.ticketnumber = b.ticketnumber and
a.status = 'Completed'
order by b.YOUR_DATETIME_FIELD DESC LIMIT 0,50

也许对你有帮助。