Mysql 是否可以将联接添加到此SQL语句？

我有一个表和一个查询，用来返回进球最多的球员名单

查询非常有效，但是为了获得用户名，我必须根据返回的结果（player_id）执行另一个查询

是否可以修改我现有的查询以连接两个表？我知道这在普通查询中是可能的，我只是不确定它是否在这个实例中，因为将返回自定义结果表

这是我的初始表，名为

结果
：

+----------------+-------------+-----+
| Field          | Type        | Key |
+----------------+-------------+-----+
| results_id     | int         | Pri |
| community_id   | int         |     |
| player1_id     | int         |     |
| player1_goals  | int         |     |
| player2_id     | int         |     |
| player2_goals  | int         |     |
+----------------+-------------+-----+

这是我用来返回结果的查询：

select player, sum(goals) from 
((select player1_id as player, player1_goals as goals from results where community_id = 5 ) 
union all 
(select player2_id as player, player2_goals as goals from results where community_id = 5 ) 
) p 
group by player 
order by sum(goals) desc

我的结果就是这样返回的：

+----------------+------------+
| Player         | sum(goals) |
+----------------+------------+
| 2              | 94         |
| 14             | 63         |
| 7              | 43         |
+----------------+------------+

是否可以修改上述查询并将
join
添加到我的
users
表中：

+--------+-----------+
| id     | user_name  |
+---------------------+
| 2      | John       |
| 7      | Andrew     |
| 14     | Charles    |
+--------+------------+

要获得以下内容的输出：

+----------------+----------------+------------+
|user_name       | Player         | sum(goals) |
+----------------+----------------+------------+
| John           | 2              | 94         |
| Charles        | 14             | 63         |
| Andrew         | 7              | 43         |
+----------------+----------------+------------+

简短回答-是的，您可以：

select u.user_name, sum(goals) from 
((select player1_id as player, player1_goals as goals from results where community_id = 5 ) 
union all 
(select player2_id as player, player2_goals as goals from results where community_id = 5 ) 
) p 
join users u on p.player = u.id
group by player 
order by sum(goals) desc

您可以通过加入
来完成。您也可以表示为：

select u.*,
       (select sum(case when u.id = r.player1_id then r.player1_goals else r.player2_goals)
        from results r
        where r.community_id = 5 and
              u.id in (r.player1_id, r.player2_id)
       ) as goals
from users u;

杰出的成功了！这就是我喜欢的一个长问题的简短答案！：）一场比赛只有两个人吗？不是每个球员都应该有一排球员表吗？