两个时间戳之间的MYSQL查询
我的DB表中有以下条目两个时间戳之间的MYSQL查询,mysql,unix-timestamp,Mysql,Unix Timestamp,我的DB表中有以下条目 eventName(varchar 100) -> myEvent date(timestamp) -> 2013-03-26 09:00:00 我尝试使用以下查询: SELECT * FROM eventList WHERE `date` BETWEEN UNIX_TIMESTAMP(1364256001) AND UNIX_TIMESTAMP(1364342399) i、 e在2013-03-26 00:00:01和2013-03-26 23:59
eventName(varchar 100) -> myEvent
date(timestamp) -> 2013-03-26 09:00:00
我尝试使用以下查询:
SELECT *
FROM eventList
WHERE `date` BETWEEN UNIX_TIMESTAMP(1364256001) AND UNIX_TIMESTAMP(1364342399)
i、 e在2013-03-26 00:00:01和2013-03-26 23:59:59之间
但它给了我0个结果
我尝试过扩大日期范围,但运气不好,结果肯定在这个范围内
非常感谢您的帮助。请尝试:
SELECT *
FROM eventList
WHERE `date` BETWEEN FROM_UNIXTIME(1364256001) AND FROM_UNIXTIME(1364342399)
或
请尝试以下操作:
SELECT * FROM eventList WHERE
date BETWEEN
STR_TO_DATE('2013/03/26', '%Y/%m/%d')
AND
STR_TO_DATE('2013/03/27', '%y/%m/%d')
试试这个。它对我有用
SELECT * FROM eventList
WHERE DATE(date)
BETWEEN
'2013-03-26'
AND
'2013-03-27'
您只需将日期转换为
UNIX\u时间戳
。您可以这样编写查询:
SELECT *
FROM eventList
WHERE
date BETWEEN
UNIX_TIMESTAMP('2013/03/26')
AND
UNIX_TIMESTAMP('2013/03/27 23:59:59');
如果不指定时间,MySQL将假定给定日期的时间为00:00:00
@Amaynut谢谢
SELECT *
FROM eventList
WHERE date BETWEEN UNIX_TIMESTAMP('2017-08-01') AND UNIX_TIMESTAMP('2017/08/01');
如上所述,代码工作正常,我的问题得到解决。请尝试下面的代码。在我的情况下工作。希望这有帮助
SELECT * FROM `orders` WHERE `order_date_time` BETWEEN 1534809600 AND 1536718364
select id,total_Hour,
(coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)) as weekday_Listing_Hrs,
(coalesce(weekend_1,0)+coalesce(weekend_2,0)+coalesce(weekend_3,0)) as weekend_Listing_Hrs
from
select *,
listing_duration_Hour-(coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)+coalesce(weekend_1,0)+coalesce(weekend_2,0)) as weekend_3
from
(
select * ,
case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (0,1,2,3,4)
then timestampdiff(hour,Start_Date,End_Date)
when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (0,1,2,3,4)
then 24-timestampdiff(hour,date(Start_Date),Start_Date)
end as weekday_1,
case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (0,1,2,3,4)
then timestampdiff(hour,date(End_Date),End_Date)
end as weekday_2,
case when date(Start_Date) != date(End_Date) then
(5*(DATEDIFF(date(End_Date),adddate(date(Start_Date),+1)) DIV 7) +
MID('0123455501234445012333450122234501101234000123450',7 * WEEKDAY(adddate(date(Start_Date),+1))
+ WEEKDAY(date(End_Date)) + 1, 1))* 24 end as weekday_3,
case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (5,6)
then timestampdiff(hour,Start_Date,End_Date)
when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (5,6)
then 24-timestampdiff(hour,date(Start_Date),Start_Date)
end as weekend_1,
case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (5,6)
then timestampdiff(hour,date(End_Date),End_Date)
end as weekend_2
from
TABLE_1
)
试试这个它对我有用
SELECT * from bookedroom
WHERE UNIX_TIMESTAMP('2020-8-07 5:31')
between UNIX_TIMESTAMP('2020-8-07 5:30') and
UNIX_TIMESTAMP('2020-8-09 5:30')
为什么有人会在查询中写入时间戳值?查看关于如何使用格式化日期的其他答案。我不知道为什么这个答案有效,尽管如果我有一个时间戳,我想使用
UNIX\u timestamp(mytimestamp)
或FROM\u UNIXTIME(mytimestamp)
在我的情况下,这两个答案都不起作用,并且使用php变量/direct timestamp有效!这不是问题的答案。请修改您的答案并提供解释。如果我创建$today\u start=DateToTimestamp(date('Y-m-d h:i:sa',strotime('today midnight'),$timezone)$today_end=DateToTimestamp(日期('Y-m-d h:i:SA',标准时间('-1秒',标准时间('明日午夜)),$时区)
并在从UNIXTIME($today\u start)到从UNIXTIME($today\u end)之间使用此
它不会返回它应该返回的内容,因此我必须直接使用变量。这一个确实适用于一个日期(以可读的形式,尽管类似于2013-03-26 00:00:01),但不适用于时间戳,就像我的情况一样,但不适用于一般情况。为什么不直接提供时间戳呢?
SELECT * from bookedroom
WHERE UNIX_TIMESTAMP('2020-8-07 5:31')
between UNIX_TIMESTAMP('2020-8-07 5:30') and
UNIX_TIMESTAMP('2020-8-09 5:30')