从另一个表ID中排序mysql数据

我不知道如何从表

webhooks

中按更大的

SUM（amount）

id排序以获取消息

网钩表

CREATE TABLE `webhooks` (
  `id` int(200) NOT NULL,
  `created_at` varchar(40) NOT NULL,
  `amount` double NOT NULL,
  `from_id` varchar(20) NOT NULL,
  `to_id` varchar(20) NOT NULL,
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

webhooks数据：

INSERT INTO `webhooks` (`to_id`, `from_id`, `amount`, `created_at`) VALUES
('1273817', '15992', 9.99, '1605642691'),
('1273817', '11813', 8, '1605642189'),
('38218', '47348', 5.99, '1605642142'),
('188277', '39123', 8, '1605641928'),
('188277', '47348', 10, '1605639932');

消息表：

CREATE TABLE `messages` (
  `id` int(255) NOT NULL,
  `to_id` int(20) NOT NULL,
  `from_id` int(20) NOT NULL,
  `message` longtext NOT NULL,
  `time` double NOT NULL,
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

信息数据：

INSERT INTO `messages` (`from_id`, `to_id`, `message`, `time`) VALUES
(1273817, 43802, 'Hey there how are you', 1605643518.3869),
(46804, 1273817, 'Hello there!!', 1605643487.5376),
(45937, 1273817, 'Wowww', 1605642552.2655),
(47348, 38218, 'yayyy!!!', 1605642523.0497),
(47348, 43802, 'Are you there?', 1605640241.813);

这是我的邮件查询，但我必须按最大webhooks金额

到\u id

总和（金额）

排序

---

所需的结果应与查询相同，但不是按时间顺序描述，而是从

webhooks

表中按总和（金额）描述进行排序。

与

webhooks

表连接并使用

分组方式from\u id，to\u id

，然后可以按总和（金额）描述进行排序

SELECT
   c.from_id,
   c.to_id 
FROM
   messages c 
   JOIN
      (
         SELECT
            CASE
               WHEN
                  `from_id` = '$uid' 
               THEN
                  `to_id` 
               ELSE
                  `from_id` 
            END
            AS other, MAX(time) AS latest 
         FROM
            messages 
         WHERE
            (
               `from_id` = '$uid' 
               OR `to_id` = '$uid'
            )
            AND to_id != '0' 
         GROUP BY
            other
      )
      m 
      ON (c.from_id = '$uid' 
        AND c.to_id = m.other 
        OR c.to_id = '$uid' 
        AND c.from_id = m.other) 
        AND c.time = m.latest 
LEFT JOIN (
    SELECT 0 + from_id AS from_id_int, 0 + to_id AS to_id_int, SUM(amount) AS amount
    FROM webhooks
    GROUP BY from_id, to_id
) AS w ON w.from_id_int = c.from_id AND w.to_id_int = c.to_id
ORDER BY w.amount DESC
LIMIT $offset, $limit

---

提示：不要执行literal

“$uid”

，而是执行

？

，然后将值绑定到这些值。@tadman感谢您的提示。请参阅与

webhooks

表连接，然后按

顺序使用所需的列。请显示此示例数据的结果。注释不用于扩展讨论；这段对话已经结束。
SELECT
   c.from_id,
   c.to_id 
FROM
   messages c 
   JOIN
      (
         SELECT
            CASE
               WHEN
                  `from_id` = '$uid' 
               THEN
                  `to_id` 
               ELSE
                  `from_id` 
            END
            AS other, MAX(time) AS latest 
         FROM
            messages 
         WHERE
            (
               `from_id` = '$uid' 
               OR `to_id` = '$uid'
            )
            AND to_id != '0' 
         GROUP BY
            other
      )
      m 
      ON (c.from_id = '$uid' 
        AND c.to_id = m.other 
        OR c.to_id = '$uid' 
        AND c.from_id = m.other) 
        AND c.time = m.latest 
LEFT JOIN (
    SELECT 0 + from_id AS from_id_int, 0 + to_id AS to_id_int, SUM(amount) AS amount
    FROM webhooks
    GROUP BY from_id, to_id
) AS w ON w.from_id_int = c.from_id AND w.to_id_int = c.to_id
ORDER BY w.amount DESC
LIMIT $offset, $limit