Mysql 填写数据和缺少的日期

我正在尝试使用SQL获取当前查询结果：

+------------+------------+------------+ | STORE_NUM | PRICE | DATE_CHNG | +------------+------------+------------+ | 100 | 1.50 | 2014-05-01 | | 100 | 1.52 | 2014-05-03 | | 100 | 1.48 | 2014-05-05 | | 100 | 1.51 | 2014-05-10 | +------------+------------+------------+ +------------+------------+------------+ |门店数量、价格、日期、变化| +------------+------------+------------+ | 100 | 1.50 | 2014-05-01 | | 100 | 1.52 | 2014-05-03 | | 100 | 1.48 | 2014-05-05 | | 100 | 1.51 | 2014-05-10 | +------------+------------+------------+ 让他们看起来更像这样，添加了缺失的日期，但也填入了价格的价值：

+------------+------------+------------+ | STORE_NUM | PRICE | DATE_CHNG | +------------+------------+------------+ | 100 | 1.50 | 2014-05-01 | | 100 | 1.50 | 2014-05-02 | | 100 | 1.52 | 2014-05-03 | | 100 | 1.52 | 2014-05-04 | | 100 | 1.48 | 2014-05-05 | | 100 | 1.48 | 2014-05-06 | | 100 | 1.48 | 2014-05-07 | | 100 | 1.48 | 2014-05-08 | | 100 | 1.48 | 2014-05-09 | | 100 | 1.51 | 2014-05-10 | +------------+------------+------------+ +------------+------------+------------+ |门店数量、价格、日期、变化| +------------+------------+------------+ | 100 | 1.50 | 2014-05-01 | | 100 | 1.50 | 2014-05-02 | | 100 | 1.52 | 2014-05-03 | | 100 | 1.52 | 2014-05-04 | | 100 | 1.48 | 2014-05-05 | | 100 | 1.48 | 2014-05-06 | | 100 | 1.48 | 2014-05-07 | | 100 | 1.48 | 2014-05-08 | | 100 | 1.48 | 2014-05-09 | | 100 | 1.51 | 2014-05-10 | +------------+------------+------------+ 非常感谢您提供的任何帮助/建议/资源

谢谢

试试看：

SELECT "STORE_NUM", "PRICE", "DATE_CHNG" + x - 1 As "DATE_CHNG"
FROM (
  SELECT *,
       Lead("DATE_CHNG") OVER (Order By "DATE_CHNG" ) - "DATE_CHNG" As number_of_days
  FROM table1
) m,
LATERAL (
  SELECT generate_series( 1, 
                         CASE coalesce(m.number_of_days, 1)
                         WHEN 0 THEN 1
                         ELSE coalesce(m.number_of_days, 1) END) x
) y

演示==>

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此查询仅适用于9.3版，早期版本不支持横向联接

创建日期帮助表，联接。使用代码而不是查询。如果查询失败，请使用google。标记实际使用的数据库，而不仅仅是随机标记其中的一些数据库