MySQL使用group by选择查询中的总行数

我需要知道查询的总结果，我使用的是COUNT（） 问题是，在这个查询中，我有一个groupby

我得到的结果是5行，每行的结果总数为5行

SELECT  COUNT(c.id) AS tot
FROM    contributors AS c LEFT JOIN contributors_info AS ci 
        ON c.id = ci.idcontributor
WHERE   c.state = 'active'
GROUP BY c.id
ORDER BY c.id ASC

我的查询结果是

|c.id| | 1 | | 2 | | 1 | | 1 | | 1 | |c、 身份证| | 1 | | 2 | | 1 | | 1 | | 1 | 尝试下面的查询

 SELECT COUNT(*) as tot FROM(
    SELECT  c.id 
    FROM    CONTRIBUTORS AS c LEFT JOIN contributors_info AS ci 
        ON c.id = ci.idcontributor
    WHERE   c.state = 'active'
    GROUP BY c.id
    ORDER BY c.id ASC
) AS tmp

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您的查询工作正常，现在是否比使用SQL\u CALC\u FOUND\u行更快？