Mysql 最常见的星期查询

有此查询：

SELECT HOUR( DATE ) AS hr, COUNT( * ) AS cnt
FROM users
GROUP BY hr
ORDER BY cnt DESC

DATE是一个DATETIME字段，上面的查询显示了DATE字段中最常见的小时数

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我正在尝试改进它，但不知道如何做，我想将它按周天数和周内天数细分为最常见的时间。

请告诉我以下是否有效：

SELECT dayname(DATE) as week_day,HOUR( DATE ) AS hr, COUNT( * ) AS cnt 
FROM users 
GROUP BY week_day, hr ORDER BY cnt DESC

请尝试此查询-

SELECT
  DAYOFWEEK(DATE) AS wd,
  HOUR(DATE) AS hr,
  COUNT(*) AS cnt
FROM 
 users
GROUP BY
  wd, hr
ORDER BY
  cnt DESC

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这给了我比我预期的更多的结果（尽管确实有效）。我正在寻找一个分类：Sun/Mon/Tue/Wed/Thu/Fri/Sat，然后在最常见的时间内。然后尝试更改组byWorks中列的顺序太棒了！，我如何知道第一天的数字1是星期天还是星期一？DAYOFWEEK始终返回1=星期天，依此类推。您可以使用DATE_格式函数，例如-DATE_格式（日期，'%a'））

SELECT
  DATE_FORMAT(DATE, '%a') AS wd, -- or DATE_FORMAT(DATE, '%W')
  HOUR(DATE) AS hr,
  COUNT(*) AS cnt
FROM 
 users
GROUP BY
  wd, hr
ORDER BY
  cnt DESC