MySQL group by，具有多个列和，每个组的总和

我有一张这样的桌子：

Votes (id, person, positive_vote, negative_vote)

我想按个人分组，并按每个人的总投票数排序。我知道如何计算一组人的单列总票数，但我不知道如何计算每组人的总票数

以下是我目前掌握的情况：

SELECT person, sum(positive_vote), sum(negative_vote) FROM Votes GROUP BY person;

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如果您想要每个人的总票数，只需减去总票数，或者如果您只想要总票数，则将其相加：

SELECT person, sum(positive_vote), sum(negative_vote),
    SUM(positive_vote)-SUM(negative_vote)
FROM Votes 
GROUP BY person

请注意，我在这里减去了总和，而没有对列本身的差值求和，因为我不知道如何在表中存储数据，空值可以在数学上做一些有趣的事情。

试试

SELECT person, 
       sum(positive_vote) totalPositive, 
       sum(negative_vote) totalNegative,
       (sum(positive_vote) + sum(negative_vote)) totalVotes
FROM Votes 
GROUP BY person
-- HAVING (sum(positive_vote) + sum(negative_vote)) < 5

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你是说赞成票和反对票的总和吗

SELECT 
  person, 
  SUM(positive_vote) AS positive_votes, 
  SUM(negative_vote) AS negative_votes,
  SUM(positive_vote + negative_vote) AS total_votes
FROM Votes GROUP BY person;

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你知道有没有可能在全票上加一个WHERE？我有个错误。我在末尾加了这样一个词：“一组一组，总票数<5；”@ScottBartell使用having代替where，使用sumpositive_vote+sumnegative_vote<5FYI：我必须使用IFNULLSUMcol1，0+IFNULLSUMcol2，0。否则，计算失败，结果为空。

SELECT 
  person, 
  SUM(positive_vote) AS positive_votes, 
  SUM(negative_vote) AS negative_votes,
  SUM(positive_vote + negative_vote) AS total_votes
FROM Votes GROUP BY person;

SELECT person, 
       sum(positive_vote) as totalPositive, 
       sum(negative_vote) as totalNegative,
       (sum(positive_vote + negative_vote)) as totalVotes
FROM Votes 
GROUP BY person