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Mysql 与最近创建的第一个条目左连接_Mysql_Sql_Symfony_Doctrine Orm_Greatest N Per Group - Fatal编程技术网

Mysql 与最近创建的第一个条目左连接

Mysql 与最近创建的第一个条目左连接,mysql,sql,symfony,doctrine-orm,greatest-n-per-group,Mysql,Sql,Symfony,Doctrine Orm,Greatest N Per Group,我有一个相当复杂的查询,如下所示: return $this->createQueryBuilder('s') ->select('s') ->addSelect('COUNT(p.id) as HIDDEN c_id') ->leftJoin('s.owner', 'o') ->leftJoin('s.userPictures', 'p

我有一个相当复杂的查询,如下所示:

return $this->createQueryBuilder('s')
                ->select('s') 
                ->addSelect('COUNT(p.id) as HIDDEN c_id')
                ->leftJoin('s.owner', 'o')
                ->leftJoin('s.userPictures', 'p')
                ->leftJoin('o.transactions', 't')
                ->leftJoin('t.packType', 'pt')
                ->where('pt.id =:packId')
                ->setParameter('packId', $packId)
                ->andWhere('s.expirydate >=:expiryDate')
                ->setParameter('expiryDate', new \DateTime('now'))
                ->andWhere('c_id <:numberOfPictures')
                ->setParameter('numberOfPictures', $numberOfPictures)
                ->orderBy("c_id", 'DESC')
                ->groupBy('p.id')
                ->getQuery()
                ;

看一看,上一个解决方案使用了
左连接
@MatTheCat不理解左连接如何解决这个问题“左连接的工作原理是当[t1.created]处于其最大值时,没有[t2.created]具有更大的值,s2行的值将为空。”
class Transaction
{


    /**
     * @var datetime $created
     * @Gedmo\Timestampable(on="create")
     * @ORM\Column(type="datetime")
     */
    protected $created;
}