如何从MySQL中PK最低的第二个tbl中选择2个tbl，但仅选择1行？

结构：

tbl 1

tbl 2

我的问题是：

SELECT *
FROM cars c
LEFT JOIN imgs g
ON c.car_id=g.car_id
WHERE 1

结果:

|img_id(PK)| car_id| make  | model | year |   img_link    |
-----------------------------------------------------------
|     1    |    1  | Toyot | Camry | 1999 |  tcamry1.jpeg |
|     2    |    1  | Toyot | Camry | 1999 |  tcamry2.jpeg |
|     3    |    1  | Toyot | Camry | 1999 |  tcamry3.jpeg |
|     4    |    2  | Honda | Civic | 2005 |  hcivic1.jpeg |
|     5    |    2  | Honda | Civic | 2005 |  hcivic2.jpeg |

我需要为每辆车取一行，并且有WHERE子句，其中包含与同一辆车相关的所有img_id中的最低img_id值

我想要的结果是：

|img_id(PK)| car_id| make  | model | year |   img_link    |
-----------------------------------------------------------
|     1    |    1  | Toyot | Camry | 1999 |  tcamry1.jpeg |
|     4    |    2  | Honda | Civic | 2005 |  hcivic1.jpeg |

多谢各位

更新：

我需要这样的东西：-/

SELECT g.id, c.car_id, c.mc_make, c.mc_model, c.mc_year, c.mc_desc
FROM mycars c
INNER JOIN (SELECT * FROM mycars_gallery g WHERE )
ON c.car_id=g.car_id
WHERE g.id = min(g.id)

试试这个。。但不确定。

试试：

SELECT *
FROM cars c
LEFT JOIN imgs g
ON c.car_id=g.car_id
WHERE img_id IN(SELECT MIN(img_id)) GROUP BY model

演示：

---

希望这有帮助。

我觉得我需要看看min（）函数，请参阅上面的更新。我只是不知道正确的语法

SELECT g.id, c.car_id, c.mc_make, c.mc_model, c.mc_year, c.mc_desc
FROM mycars c
INNER JOIN (SELECT * FROM mycars_gallery g WHERE )
ON c.car_id=g.car_id
WHERE g.id = min(g.id)

SELECT *
FROM cars c
LEFT JOIN imgs g
ON c.car_id=g.car_id
WHERE 1
GROUP BY g.img_link;

SELECT *
FROM cars c
LEFT JOIN imgs g
ON c.car_id=g.car_id
WHERE img_id IN(SELECT MIN(img_id)) GROUP BY model

SELECT MIN(b.img_id), a.car_id, a.make, a.model, a.year, b.img_link 
FROM cars a 
LEFT JOIN imgs b ON a.car_id = b.car_id 
GROUP BY a.car_id, a.make, a.model, a.year ;