Mysql 使用关联对无效值[对象承诺]进行续集

我目前的型号：

let Book = sequelize.define('book', {
  title: Sequelize.STRING,
  author: Sequelize.STRING,
  ...
});

let Recommendation = sequelize.define('recommendations', {
  reasoning: Sequelize.STRING,
  rating: Sequelize.FLOAT,
});

Book.belongsToMany(Recommendation, {through: 'bookrecommendation'});
Recommendation.belongsToMany(Book, {through: 'bookrecommendation'});

当执行addRecommension方法下面的代码来为Book添加建议时，我得到一个错误：无效值[对象承诺]

Book.findOrCreate({
  where: { id: '1' }, defaults: {
    author: 'test',
    title: 'test'
  }
})
.spread(function (b, createdBook) {
const rec = Recommendation.create(
  {
    reasoning: 'test',
    rating: 1
  });
  b.addRecommendation(rec).then((result) => {

  }, (error) => {
    console.log(error);
  })
}

---

这里的问题是，

rec

是一种承诺。 这应该可以解决问题

Book.findOrCreate({ where: { id: '1' }, defaults: {
  author: 'test',
  title: 'test'
}}).spread(function (b, createdBook) {
Recommendation.create({
 reasoning: 'test',
 rating: 1
}).then((rec) => {
  b.addRecommendation(rec).then((result) => {}, (error) => {
    console.log(error);
   })
})

---

这里的问题是，

rec

是一种承诺。 这应该可以解决问题

Book.findOrCreate({ where: { id: '1' }, defaults: {
  author: 'test',
  title: 'test'
}}).spread(function (b, createdBook) {
Recommendation.create({
 reasoning: 'test',
 rating: 1
}).then((rec) => {
  b.addRecommendation(rec).then((result) => {}, (error) => {
    console.log(error);
   })
})

---

这当然管用，我没想到这个。谢谢。当然行了，我没想到那个。谢谢