Mysql 我可以选择上一行和下一行具有条件的具有条件的行吗？

我正在使用MYSQL，正在寻找一种方法，只选择上一行，下一行有一个名为fav_num的字段，其值为“3”

例如，我有6行和两个字段。字段为ID和fav_编号

 ID| fav_num
 1 | 3
 2 | 2
 3 | 3
 4 | 7
 5 | 2
 6 | 9

我想找到一种方法，从上一行和下一行fav_num为3的表中返回ID。 然后，此查询将返回ID 2

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如果我的问题听起来令人困惑，我道歉

我认为这可以奏效

SELECT id
  FROM tab t
 WHERE t.id BETWEEN
       (SELECT MAX(id) FROM tab tp WHERE tp.id < t.id AND tp.fav_num = 3)
   AND (SELECT MIN(id) FROM tab tn WHERE tn.id > t.id AND tn.fav_num = 3)

请试试这个：

SELECT a.id FROM test1 a WHERE 
3=(SELECT fav_num FROM test1 WHERE id = (SELECT MAX(id) FROM test1 WHERE id <a.id)) AND 
3=(SELECT fav_num FROM test1 WHERE id = (SELECT MIN(id) FROM test1 WHERE id >a.id)) ;


SELECT a.id FROM test1 a WHERE 
EXISTS (SELECT 1 FROM test1 WHERE id = (SELECT MAX(id) FROM test1 WHERE     id <a.id) AND fav_num=3) AND 
EXISTS (SELECT 1 FROM test1 WHERE id = (SELECT MIN(id) FROM test1 WHERE  id >a.id)  AND fav_num=3) ;

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我不确定性能。

您是否特别希望只返回ID=2的数据，或者这是获取数据库中fav_num=2的所有条目的一般规则？ID是否始终连续无间隙？

SELECT t1.*
FROM t1
INNER JOIN (SELECT 
    @d1:=0+@d2 d1,
    @d2:=0+@d3 d2,
    @d3:=fav_num d3,
    @previd:=@id prevID,
    @id:=id 
FROM (
  SELECT *
  FROM t1 
  ORDER BY id) t
) filter
ON filter.d1 = 3
   AND filter.d3 = 3
   AND t1.id = filter.prevID
;

SELECT a.id FROM test1 a WHERE 
3=(SELECT fav_num FROM test1 WHERE id = (SELECT MAX(id) FROM test1 WHERE id <a.id)) AND 
3=(SELECT fav_num FROM test1 WHERE id = (SELECT MIN(id) FROM test1 WHERE id >a.id)) ;


SELECT a.id FROM test1 a WHERE 
EXISTS (SELECT 1 FROM test1 WHERE id = (SELECT MAX(id) FROM test1 WHERE     id <a.id) AND fav_num=3) AND 
EXISTS (SELECT 1 FROM test1 WHERE id = (SELECT MIN(id) FROM test1 WHERE  id >a.id)  AND fav_num=3) ;