Mysql wordpress中的元键和元值查询

我正在wordpress中成功运行一个查询

SELECT wp_posts.*, wp_postmeta.meta_value FROM wp_posts, wp_postmeta, wp_term_relationships, wp_terms 
WHERE term_id = '12' AND term_taxonomy_id = '12' AND ID = post_id 
AND ID = object_id AND post_type = 'property' AND post_status = 'publish' 
AND meta_key = 'property_amount' AND replace( replace(meta_value, ',', ''), '"', '' ) >= 1 
GROUP BY wp_posts.ID ORDER BY replace( replace(meta_value, ',', ''), '"', '' ) DESC 
LIMIT 0, 10

但我想在上面的查询中再添加一个meta_键及其值条件，所以我将查询更改为

  SELECT wp_posts.*, wp_postmeta.meta_value FROM wp_posts, wp_postmeta, wp_term_relationships, wp_terms 
  WHERE term_id = '12' AND term_taxonomy_id = '12' AND ID = post_id
  AND ID = object_id AND post_type = 'property' AND post_status = 'publish' 
  AND meta_key = 'property_amount' AND replace( replace(meta_value, ',', ''), '"', '' )
>= 1
  AND meta_key="property_land_type" and meta_value IN ('L','H','C')
  GROUP BY wp_posts.ID ORDER BY replace( replace(meta_value, ',', ''), '"', '' ) DESC 
  LIMIT 0, 10

在第一个查询中，下一行是额外的

meta_key="property_land_type" and meta_value in ('L','H','C')

但它不起作用。如何做到这一点。这次我不能写WP_查询，因为我有很多其他基于此查询的查询

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提前感谢

在第二个查询中，您有两个相互矛盾的条件：

meta\u key='property\u amount'和meta\u key=“property\u land\u type”

---

没有结果同时满足这两个条件

在第二个查询中，您有两个相互矛盾的条件：

meta\u key='property\u amount'和meta\u key=“property\u land\u type”

---

没有结果同时满足这两个条件

对于一个列，您有多个meta\u键，对于meta\u键和value-like，您需要

IN（）

meta_key IN( 'property_amount','property_land_type') 
AND meta_value IN ('L','H','C',replace( replace(meta_value, ',', ''), '"', '' ) >= 1)

请尝试此查询

SELECT wp_posts.*, wp_postmeta.meta_value FROM 
wp_posts, wp_postmeta, wp_term_relationships, wp_terms 
WHERE term_id = '12' AND term_taxonomy_id = '12' AND ID = post_id 
AND ID = object_id AND post_type = 'property' AND post_status = 'publish' 
AND meta_key IN( 'property_amount','property_land_type') 
AND meta_value IN ('L','H','C',replace( replace(meta_value, ',', ''), '"', '' ) >= 1)
GROUP BY wp_posts.ID ORDER BY replace( replace(meta_value, ',', ''), '"', '' ) DESC 
LIMIT 0, 10

编辑

用join试试这个，我已经加入了两次wp_Posteta，获得了两个meta_密钥

SELECT wp.*, wpm1.meta_value AS `propert_type`,
wpm2.meta_value AS `property_amount`
FROM 
wp_posts  wp
LEFT JOIN wp_postmeta wpm1 ON (wp.ID = wpm1.post_id)
LEFT JOIN wp_postmeta wpm2 ON (wp.ID = wpm2.post_id)
INNER JOIN wp_term_relationships wptr ON (wp.ID = wptr.object_id)
INNER JOIN `wp_term_taxonomy` wptt ON (wptr.term_taxonomy_id = wptt.term_taxonomy_id)
INNER JOIN wp_terms wpt ON (wptt.term_id = wpt.term_id)

WHERE wpt.term_id = '12' AND wptr.term_taxonomy_id = '12' 
AND  wp.post_type = 'property' AND wp.post_status = 'publish'
AND wpm1.meta_key = 'property_land_type' 
AND wpm2.meta_key = 'property_amount'
AND REPLACE( REPLACE(wpm2.meta_value, ',', ''), '"', '' ) >= 1
AND wpm1.meta_value IN ('L','H','C') AND  wpm1.meta_value IS NOT NULL AND  wpm2.meta_value IS NOT NULL 
GROUP BY wp.ID ORDER BY REPLACE( REPLACE(wpm2.meta_value, ',', ''), '"', '' ) DESC 
LIMIT 0, 10

---

在（）中有多个meta_键对应一列，meta_键和value like都需要

IN

meta_key IN( 'property_amount','property_land_type') 
AND meta_value IN ('L','H','C',replace( replace(meta_value, ',', ''), '"', '' ) >= 1)

请尝试此查询

SELECT wp_posts.*, wp_postmeta.meta_value FROM 
wp_posts, wp_postmeta, wp_term_relationships, wp_terms 
WHERE term_id = '12' AND term_taxonomy_id = '12' AND ID = post_id 
AND ID = object_id AND post_type = 'property' AND post_status = 'publish' 
AND meta_key IN( 'property_amount','property_land_type') 
AND meta_value IN ('L','H','C',replace( replace(meta_value, ',', ''), '"', '' ) >= 1)
GROUP BY wp_posts.ID ORDER BY replace( replace(meta_value, ',', ''), '"', '' ) DESC 
LIMIT 0, 10

编辑

用join试试这个，我已经加入了两次wp_Posteta，获得了两个meta_密钥

SELECT wp.*, wpm1.meta_value AS `propert_type`,
wpm2.meta_value AS `property_amount`
FROM 
wp_posts  wp
LEFT JOIN wp_postmeta wpm1 ON (wp.ID = wpm1.post_id)
LEFT JOIN wp_postmeta wpm2 ON (wp.ID = wpm2.post_id)
INNER JOIN wp_term_relationships wptr ON (wp.ID = wptr.object_id)
INNER JOIN `wp_term_taxonomy` wptt ON (wptr.term_taxonomy_id = wptt.term_taxonomy_id)
INNER JOIN wp_terms wpt ON (wptt.term_id = wpt.term_id)

WHERE wpt.term_id = '12' AND wptr.term_taxonomy_id = '12' 
AND  wp.post_type = 'property' AND wp.post_status = 'publish'
AND wpm1.meta_key = 'property_land_type' 
AND wpm2.meta_key = 'property_amount'
AND REPLACE( REPLACE(wpm2.meta_value, ',', ''), '"', '' ) >= 1
AND wpm1.meta_value IN ('L','H','C') AND  wpm1.meta_value IS NOT NULL AND  wpm2.meta_value IS NOT NULL 
GROUP BY wp.ID ORDER BY REPLACE( REPLACE(wpm2.meta_value, ',', ''), '"', '' ) DESC 
LIMIT 0, 10

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你收到了什么错误消息？你收到了什么错误消息？我又收到了一个测试用例，其中这个查询不起作用（如果我有一个没有任何属性类型的记录，这意味着它是空的，但它的价格大于1。在这种情况下，它也会记录，因为金额>1，这是可以的，但我有很多基于搜索和排序的查询。所以你能告诉我，没有连接意味着只使用2倍的postmeta表。我又得到了一个测试用例，其中包含此查询。）不起作用，dude.：（如果我有一个记录没有任何属性_land _type，这意味着它是空的，但它的价格大于1，在这种情况下，它也会接受该记录，因为金额>1，这是可以的，但我有很多基于搜索和排序的查询。因此，你能告诉我没有连接意味着只使用2倍的Posteta表吗。