MySQL查询以获取两个日期范围内的订单

我正在尝试执行一个查询，为每种服务类型提供两个日期范围内的订单总数

orderDate   serviceType revenue
2014-01-01  1           3.00
2014-01-02  2           4.00
2014-01-01  1           5.00
2014-01-03  3           3.00
2014-01-02  1           4.00
2014-01-04  2           5.00
2014-01-20  1           4.00
2014-01-21  2           5.00
2014-01-23  1           6.00
2014-01-24  3           4.00
2014-01-20  1           5.00
2014-01-21  2           6.00

获取一个日期范围内的订单总数和收入的查询很简单：

select serviceType, count(*) as totalOrders, sum(revenue) as totalRevenue
from   orders 
where  orderDate >= '2014-01-01' 
   and orderDate <= '2014-01-05'
group by serviceType

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只需在两个子查询上使用联接，如未经测试的：

select o1.serviceType, totalOrders_1, totalRevenue_1, totalOrders_2, totalRevenue_2
from
(select serviceType, count(*) as totalOrders_1, sum(revenue) as totalRevenue_1
from   orders 
where  orderDate >= '2014-01-01' 
   and orderDate <= '2014-01-05'
group by serviceType) o1
inner join
(select serviceType, count(*) as totalOrders_2, sum(revenue) as totalRevenue_2
from   orders 
where  orderDate >= '2014-02-01' 
   and orderDate <= '2014-02-05'
group by serviceType) o2 using (serviceType)

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虽然不是很优雅，但pivot解决方案实际上会有类似的处理成本。

为了在这两个时段中包含给定服务类型计数为零的行，您可以执行以下操作：

SELECT o.serviceType
     , SUM(IF(o.orderDate >= '2014-01-01' AND o.orderDate <= '2014-01-05'
             ,1,0)
       ) AS totalOrders_1
     , SUM(IF(o.orderDate >= '2014-01-01' AND o.orderDate <= '2014-01-05'
             ,o.revenue,0)
       ) AS totalRevenue_1
     , SUM(IF(o.orderDate >= '2014-02-01' AND o.orderDate <= '2014-02-05'
             ,1,0)
       ) AS totalOrders_2
     , SUM(IF(o.orderDate >= '2014-02-01' AND o.orderDate <= '2014-02-05'
             ,o.revenue,0)
       ) AS totalRevenue_2
  FROM orders o
 WHERE (o.orderDate >= '2014-01-01' AND o.orderDate <= '2014-01-05')
    OR (o.orderDate <= '2014-02-01' AND o.orderDate <= '2014-02-05')
 GROUP BY o.serviceType

serviceType totalOrders_1 totalRevenue_1 totalOrders_2   totalRevenue_2
4           1             111.00         0               0.00
5           0             0.00           2               444.44

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google this:pivot表应该可以工作，但最外层的SELECT需要FROM。第二个日期范围实际上返回了Rowsys我添加了From我认为这是完美的-我会在几分钟内确认并投票。谢谢注意，使用这种方法，不可能返回计数为零值的行。若在内联视图查询o1或o2的时间范围内并没有具有给定服务类型的行，则查询不会返回给定服务类型的行。我们可以使用外部连接操作来处理一端或另一端，但MySQL中不支持完全外部连接。

serviceType totalOrders_1 totalRevenue_1 totalOrders_2   totalRevenue_2
4           1             111.00         0               0.00
5           0             0.00           2               444.44