Mysql 数据库查询失败：字段列表中的列“id”不明确

我多次尝试修改它，但此错误消息不会消失。数据库查询失败：字段列表中的“id”列不明确。有没有办法解决这个问题？

改变一下：

       SELECT  realestate.id,node.id,node.name
                from realestate,
                (SELECT
                    GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,id
                  FROM
                    address AS node JOIN address AS parent
                    ON node.lft BETWEEN parent.lft AND parent.rgt  
                  WHERE node.lft >={$lft} and node.rgt <={$rgt}
                  GROUP BY node.name) as node
        INNER JOIN users ON id_user = users.id
        LEFT JOIN pic ON id_realestate = realestate.id
        WHERE node.id = realestate.address_id

与

您需要指定表的别名，因为假设两个表都有一个名为id的列，mysql不知道使用哪个表来获取id列。

更改此选项：

       SELECT  realestate.id,node.id,node.name
                from realestate,
                (SELECT
                    GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,id
                  FROM
                    address AS node JOIN address AS parent
                    ON node.lft BETWEEN parent.lft AND parent.rgt  
                  WHERE node.lft >={$lft} and node.rgt <={$rgt}
                  GROUP BY node.name) as node
        INNER JOIN users ON id_user = users.id
        LEFT JOIN pic ON id_realestate = realestate.id
        WHERE node.id = realestate.address_id

与

---

您需要指定表的别名，因为假设两个表都有一个名为id的列，mysql不知道使用哪个表来获取id列。

问题在于子查询

GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,node.id

---

您应该指定ID来自哪个表，因为节点和父节点都包含导致歧义的ID。可能是node.ID或parent.ID

问题出在子查询上

GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,node.id

---

您应该指定ID来自哪个表，因为节点和父节点都包含导致歧义的ID。它可以是node.ID或parent.ID

这是因为您在串联查询中使用的是ID，所以它不明确，只需更改即可避免错误

SELECT  GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,
        id  -- <<== HERE (change to node.ID or parent.ID)
FROM    address AS node 
        JOIN address AS parent
           ON node.lft BETWEEN parent.lft AND parent.rg

---

这是因为您在连接查询中使用的是id，所以它是不明确的，只需更改即可避免错误

SELECT  GROUP_CONCAT(parent.name_en ORDER BY parent.lft DESC) AS name,
        id  -- <<== HERE (change to node.ID or parent.ID)
FROM    address AS node 
        JOIN address AS parent
           ON node.lft BETWEEN parent.lft AND parent.rg

---

+1顺便说一句，sql注释是-not/:+1顺便说一句，sql注释是-not/:+1用于解释+1用于解释提醒我，我们为什么要获取父ID？提醒我，我们为什么要获取父ID？