mysql查询重复数和输出格式

我有我的数据的这种表示，其中col1是recID（int），col2是version（varchar），col3是patch（int）

本表中有重复项（rec 36,37）：

我使用此查询为我提供DUP：

select recID,
 count(Version) as Count,
       Version
from Test
group by Version
having count > 1;

输出：

recID  Count  Version  Patch
32     3      434       -

如何修复此查询？我想列出recID，这是错误的，因为recID不是dup，但有空值

但是我想要的是给我DUP的版本，并以这种方式列出（如果可能的话） 预期产出：

recID  Count  Version  Patch 
32  1   5.1.4 434   -
36  2   5.1.4 434   p2
37  -   5.1.4 434   p2

---

您可以使用变量获得预期的输出

select recID, version, patch, 
       case when @prevValue = version 
           then @cnt:=@cnt+1 
           else  @cnt:=0 
           end as DupCount, 
       @prevValue:=version as var_version 
FROM Table1, ( select @prevValue := NULL , @cnt:=0 ) t
order by version

---

您可以使用下面的查询，它将给出您需要的结果

    select t1.recID,t1.Version,t1.Patch,t2.cnt,
    case when exists(select * from #tmp where t1.recID > #tmp.recID and t1.Patch=#tmp.Patch and   t1.Version=#tmp.Version ) then 0 else t2.cnt end as cnt2
    from #tmp t1 inner join (
   select Version,Patch ,COUNT(recId) as cnt from #tmp
   group by Version,Patch)t2
    on t1.Patch=t2.Patch and t1.Version=t2.Version

---

谢谢你的帮助。我的计数似乎不准确。对于recID=37，我得到的dup计数为2，对于recID=36，得到的dup计数为3，对于recID=34，得到的dup计数为4

    select t1.recID,t1.Version,t1.Patch,t2.cnt,
    case when exists(select * from #tmp where t1.recID > #tmp.recID and t1.Patch=#tmp.Patch and   t1.Version=#tmp.Version ) then 0 else t2.cnt end as cnt2
    from #tmp t1 inner join (
   select Version,Patch ,COUNT(recId) as cnt from #tmp
   group by Version,Patch)t2
    on t1.Patch=t2.Patch and t1.Version=t2.Version