Mysql Sql distinct和group by布尔字段

我想计算由两个布尔列分组和非分组的某些列的不同出现次数

select count(Distinct some_column) as Uniques, sum(some_other_col)
from myTable T
where T.created_at>'2016-09-15'
group by T.col1, T.col2

此查询提供四个值

uniques when col1=true and col2=true
uniques when col1=true and col2=false
uniques when col1=false and col2=true
uniques when col1=false and col2=false

是否可以更改同一查询并获取这三个值？ 我无法结合前4个值获得该信息

uniques  (all)
uniques when col1=true 
uniques when col2=true

更新

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实际上，我想保留分组，因为我得到的和还有一些其他值。

使用条件聚合：

select count(Distinct some_column) as Uniques,
       count(distinct case when t.col1 then some_column end) as Uniques_col1_true,
       count(distinct case when t.col2 then some_column end) as Uniques_col2_true
from myTable t
where t.created_at > '2016-09-15';

---

使用条件聚合：

select count(Distinct some_column) as Uniques,
       count(distinct case when t.col1 then some_column end) as Uniques_col1_true,
       count(distinct case when t.col2 then some_column end) as Uniques_col2_true
from myTable t
where t.created_at > '2016-09-15';

试试这个

SELECT SUM(CASE WHEN col1 = TRUE
           AND col2 = TRUE THEN 1 ELSE 0 END) AS opt1,
       SUM(CASE WHEN col1 = TRUE
           AND col2 = FALSE THEN 1 ELSE 0 END) AS opt2,
FROM
    (SELECT DISTINCT col1,
                     col2,
                     somecolumn
     FROM TABLE T
     WHERE ...) AS TB

试试这个

SELECT SUM(CASE WHEN col1 = TRUE
           AND col2 = TRUE THEN 1 ELSE 0 END) AS opt1,
       SUM(CASE WHEN col1 = TRUE
           AND col2 = FALSE THEN 1 ELSE 0 END) AS opt2,
FROM
    (SELECT DISTINCT col1,
                     col2,
                     somecolumn
     FROM TABLE T
     WHERE ...) AS TB

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@阿尔伯特。不，它给出了你要的三个。但是，您可以添加其他条件以获得所需的所有值。@albert。不，它给出了你要的三个。但是，您可以添加其他条件以获得所需的所有值。