Mysql Rails如何修复表以获取任何url

在my Records index.html.erb中，我有一个带有链接标题的表，以便该表能够自行排序：

<table class="table table-hover" id="records">
  <thead>
    <tr>
      <th><%= sortable "firstname", "Frist Name"%></th>
      <th><%= sortable "lastname", "Last Name" %></th>
...

这两者的最终产品是HTML页面上的以下代码：

<th><a class="btn btn-default btn-xs" href="/records?direction=asc&amp;sort=lastname">Last Name</a></th>

我的记录模型：

  def self.search(search)
        if search
        results = where('firstname LIKE ?', "%#{search}%")
        if !results.blank? 
            results
        else
            results = where('lastname LIKE ?', "%#{search}%")   
            if !results.blank? 
                results
            else
                results
            end
        end
    else
        Record.all
    end
  end

---

我找错地方了。在我的记录控制器的更深处，我忘记了：

  def sort_column
    Record.column_names.include?(params[:sort]) ? params[:sort] : "name"
  end

  def sort_direction
    %w[asc desc].include?(params[:direction]) ? params[:direction] : "asc"
  end

我所要做的就是把“名字”换成“名字”，这就为我解决了这个问题

  def index
    if current_user.profile.title == "admin"
      @records = Record.order(sort_column + " " + sort_direction)
    else 
      if params[:search].blank? || params[:search] ==''
        @records = Record.where(loanofficer_id: current_user.id).order(sort_column + " " + sort_direction)
      else
        @records = Record.search(params[:search])
      end
    end
  end

  def self.search(search)
        if search
        results = where('firstname LIKE ?', "%#{search}%")
        if !results.blank? 
            results
        else
            results = where('lastname LIKE ?', "%#{search}%")   
            if !results.blank? 
                results
            else
                results
            end
        end
    else
        Record.all
    end
  end

  def sort_column
    Record.column_names.include?(params[:sort]) ? params[:sort] : "name"
  end

  def sort_direction
    %w[asc desc].include?(params[:direction]) ? params[:direction] : "asc"
  end