Mysql 如何根据与分组总和的平均值相比较的分组总和进行选择

我有一张由电影、类别和价格组成的表格。 现在我只想选择总价格（该类别下每部电影的所有价格之和）高于这些类别总价格平均值的类别。 我已经能够找到平均的总价格（感谢这个网站），但不能结合起来。 以下是查询：

-- Return the average sums of the price per category
SELECT AVG(sum_price)
FROM 
(
SELECT category, sum(price) AS sum_price
FROM film_list
GROUP BY category
) AS inner_query;

-- Return category and its total price
SELECT category, SUM(price)
FROM film_list
GROUP BY category;

--[Error] Return only the category with sums of price larger than the average of sum of prices
SELECT category, SUM(price)
FROM film_list
WHERE SUM(price) >
(
   SELECT AVG(sum_price)
   FROM 
   (
       SELECT category, sum(price) AS sum_price
       FROM film_list
       GROUP BY category
   ) AS inner_query
);

---

任何帮助都将不胜感激，谢谢

使用窗口函数最容易解决此问题：

SELECT c.*
FROM (SELECT category, SUM(price) AS sum_price,
             AVG(SUM(price)) OVER () as avg_total_price
      FROM film_list
      GROUP BY category
     ) c
WHERE sum_price > avg_total_price

---

使用窗口函数最容易解决此问题：

SELECT c.*
FROM (SELECT category, SUM(price) AS sum_price,
             AVG(SUM(price)) OVER () as avg_total_price
      FROM film_list
      GROUP BY category
     ) c
WHERE sum_price > avg_total_price

---

尝试添加

groupby

，然后使用

having

SELECT category, SUM(price)
FROM film_list
GROUP BY category
HAVING SUM(price) >
(
   SELECT AVG(sum_price)
   FROM 
   (
       SELECT category, sum(price) AS sum_price
       FROM film_list
       GROUP BY category
   ) AS inner_query
);

---

尝试添加

groupby

，然后使用

having

SELECT category, SUM(price)
FROM film_list
GROUP BY category
HAVING SUM(price) >
(
   SELECT AVG(sum_price)
   FROM 
   (
       SELECT category, sum(price) AS sum_price
       FROM film_list
       GROUP BY category
   ) AS inner_query
);

---

请提供示例数据和所需结果。您可能希望使用

HAVING

子句。请提供示例数据和所需结果。您可能希望使用

HAVING

子句。哇，真管用！谢谢哇，真管用！谢谢它起作用了！刚才查了OVER子句，现在我知道了窗口函数。谢谢它起作用了！刚才查了OVER子句，现在我知道了窗口函数。谢谢