基于财产Cypher neo4j的价值创建关系
我有两个客户节点,C1,C2,如果转账类型是借记,那么我想在一个方向上创建关系,如果是贷记,那么我想在相反的方向上创建关系 下面,在得到C1和C2之后,我尝试使用where子句基于财产Cypher neo4j的价值创建关系,neo4j,cypher,Neo4j,Cypher,我有两个客户节点,C1,C2,如果转账类型是借记,那么我想在一个方向上创建关系,如果是贷记,那么我想在相反的方向上创建关系 下面,在得到C1和C2之后,我尝试使用where子句 UNWIND nextHits as transfer MERGE (C1:Customer {CusNo = transfer.CusNo }) MERGE (C2:Customer {CCusNo = transfer.CCusNo }) MERGE (C1)-[:Transfer]->(C2) WHERE t
UNWIND nextHits as transfer
MERGE (C1:Customer {CusNo = transfer.CusNo })
MERGE (C2:Customer {CCusNo = transfer.CCusNo })
MERGE (C1)-[:Transfer]->(C2) WHERE transfer.type = 'Credit'
MERGE (C2)-[:Transfer]->(C1) WHERE transfer.type = 'Debit'
RETURN C1,C2
上述方法不起作用
UNWIND nextHits as transfer
MERGE (C1:Customer {CusNo = transfer.CusNo })
MERGE (C2:Customer){CusNo = transfer.CusNo })
WITH C1,C2, CASE transfer.type = 'Credit' WHEN TRUE THEN [1] ELSE [] END as creditList,
CASE transfer.type = 'Debit' WHEN TRUE THEN [1] ELSE [] END as deditList
FOREACH(x IN creditList| MERGE (C1)-[:Transfer]->(C2))
FOREACH(x IN debitList| MERGE (C2)-[:Transfer]->(C1))
RETURN C1,C2
我们在这里使用CASE表达式根据条件创建一个包含一个元素或没有元素的列表。我们遍历这个列表来创建关系。CASE transfer.type='Debit'表示转账类型为'Credit',因此creditList将有一个元素,debitList将为空。因此,我们将贷方类型关系合并为一次,借方类型关系合并为零次。
希望这有帮助:你能帮我吗?