Node.js “如何存储”；阿波罗取回“；变量中的graphql响应？

我创建了以下代码以从graphql响应返回标题、名字和姓氏。我正在使用这些返回值进行自动测试，以确认它们的值：

const { createApolloFetch } = require('apollo-fetch');

const uri = 'http://localhost:3000';

const query = `{
    Post(id: 1) {
            id
            title
            forename
            surname
    }
}
`;

const apolloFetch = createApolloFetch({ uri });

const returnApolloBody = () => {
    return apolloFetch({query}).
    then(res => res.data)
        .catch(err => {
            throw new Error(err);
        });
};

const responseForename = returnApolloBody().then(result => result.Post.forename);
const responseTitle = returnApolloBody().then(result => result.Post.title);
const responeSurname = returnApolloBody().then(result => result.Post.surname);

module.exports = {
    responseForename: responseForename,
    responseTitle: responseTitle,
    responeSurname: responeSurname,
};

然而，我意识到这不是最有效的方法，因为我正在为每个值设置一个单独的http请求。我认为将整个响应存储为JSON值会容易得多，然后从这个变量中提取值，但是我运气不太好。我有以下代码，返回的值为未定义：

const { createApolloFetch } = require('apollo-fetch');

const uri = 'http://localhost:3000';

const query = `{
    Post(id: 1) {
            id
            title
            forename
            surname
    }
}
`;

const apolloFetch = createApolloFetch({ uri });

const returnApolloBody = () => {
    return apolloFetch({query}).
    then(res => res)
        .catch(err => {
            throw new Error(err);
        });
};

const response = returnApolloBody().then(response => response);

const forename = response.then(response => response.Post.forename);
const surname = response.then(response => response.Post.surname);
const title = response.then(response => response.Post.title);


module.exports = {
    forename: forename,
    title: title,
    surname: surname
};

我缺少什么来允许我将整个响应存储在一个常量中，然后在该常量中查询特定属性

---

提前感谢

您应该能够返回结果

响应。将

作为对象发布，例如下面我正在使用Apollo客户端获取用户配置文件

apolloclient.query({
query: q_my_profile}).then(
resp => {
    resolve(resp.data.my_profile);
},
error => {
    reject(error.message);
});