Node.js express.js app.get(';/images/1.gif';…问题
我有以下代码,这是我试图构建的express应用程序的一部分:Node.js express.js app.get(';/images/1.gif';…问题,node.js,express,nowjs-sockets,Node.js,Express,Nowjs Sockets,我有以下代码,这是我试图构建的express应用程序的一部分: app.get('/stat/1.gif', function( req, res ) { var time = +new Date(); var origin; res.writeHead(200, {'Content-Type': 'image/gif'}); origin = /\/(.*)\.gif/.exec(req.url); console.log(origin); if
app.get('/stat/1.gif', function( req, res ) {
var time = +new Date();
var origin;
res.writeHead(200, {'Content-Type': 'image/gif'});
origin = /\/(.*)\.gif/.exec(req.url);
console.log(origin);
if (origin) {
var ip = req.ip;
if (ip === null || ip === "127.0.0.1") {
ip = "82.246.239.187";
}
location = geoip.lookup(ip);
console.log(location);
var obj;
console.log(location.city);
console.log(location.ll[1]);
console.log(location.ll[0]);
obj = {
city: location.city
,longitude: location.ll[1]
,latitude: location.ll[0]
,ip: ip
,timestamp: time
};
console.log(obj);
everyone.now.receiveLocation(obj);
} else {
console.log( 'fixme no origin' );
}
});
查看console.log()作为obj获取
{ city: 'Nîmes',
longitude: 4.3596,
latitude: 43.8338,
ip: '82.246.239.187',
timestamp: 1359930392288 }
但我一直在犯这样的错误:
TypeError: Property 'receiveLocation' of object #<Object> is not a function
at /Users/khinester/Documents/Tutorials/Node/Blade/server.js:188:18
at callbacks (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/lib/router/index.js:161:37)
at param (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/lib/router/index.js:135:11)
at pass (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/lib/router/index.js:142:5)
at Router._dispatch (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/lib/router/index.js:170:5)
at Object.router (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/lib/router/index.js:33:10)
at next (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/node_modules/connect/lib/proto.js:199:15)
at resume (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/node_modules/connect/lib/middleware/static.js:60:7)
at SendStream.error (/Users/khinester/Documents/Tutorials/Node/Blade/node_modules/express/node_modules/connect/lib/middleware/static.js:73:37)
at SendStream.EventEmitter.emit (events.js:115:20)
这很好,但我需要使用geoip-lite作为主机,我想在其中加热它,但它没有geoip-c库
非常感谢您的建议。您如何定义
receiveLocation
?这是错误的来源,而不是您的geoip逻辑。它说它是一个对象,不是一个函数。receiveLocation在我的map.js代码中,但正如我在原始消息中所说的,当我使用goeip时,我会将相同的obj传递给每个人。现在。receiveLocation(obj);这很有效!谢谢你提供的额外信息。现在我知道了,我至少可以猜一猜。在map.js中,只有在jQuery ready回调运行后才分配该值。两个代码示例之间的主要区别是一个是异步的,另一个是同步的。也许现在你可以尝试在jQuery之前调用receiveLocation
由于时间差异,nction在客户端创建it?
app.get('/stat/1.gif', function( req, res, next ) {
var time = +new Date();
var origin;
res.writeHead(200, {'Content-Type': 'image/gif'});
origin = /\/(.*)\.gif/.exec(req.url);
if (origin) {
var ip = req.headers['x-real-ip'];
if (ip === null || ip === "127.0.0.1") {
ip = "82.246.239.187";
}
city.lookup(ip, function(err, location) {
var obj;
if ( !err && location ) {
obj = {
city: location.city
,longitude: location.longitude
,latitude: location.latitude
,ip: ip
,timestamp: time
};
} else {
console.log( 'server fake location' );
obj ={
city: 'Bexleyheath',
longitude: 0.15000000596046448,
latitude: 51.45000076293945,
ip: '86.173.61.119',
timestamp: 1343054092459
};
}
everyone.now.receiveLocation(obj);
console.log(obj);
});
console.log(origin[1], req.connection.remoteAddress, req.headers['user-agent']);
} else {
console.log( 'fixme no origin' );
}
});