Node.js 从url获取日期并返回json
使用这个简单的例子Node.js 从url获取日期并返回json,node.js,centos,Node.js,Centos,使用这个简单的例子 var server = http.createServer(function(req, res){ var output = {message: "Hello World!"}; var body = JSON.stringify(output); res.writeHead(200, { "Content-Type": "application/json", "Access-Control-Allow-Origin": "*" });
var server = http.createServer(function(req, res){
var output = {message: "Hello World!"};
var body = JSON.stringify(output);
res.writeHead(200, {
"Content-Type": "application/json",
"Access-Control-Allow-Origin": "*"
});
res.end(body);
});
我可以返回json对象。我怎样才能从这样的请求中返回一些参数
url: http://localhost:8080/get/jhon
output: {"message": "Hello jhon"}
您可以修改.htaccess文件以将URL解析为参数。有关示例,请参见此问题:您可以修改.htaccess文件以将URL解析为参数。查看此问题以获取示例:为
请求添加一个检查程序。url
基本上,以您自己的代码为例:
var server = http.createServer(function(req, res){
var output = {message: "Hello World!"};
var body = JSON.stringify(output);
res.writeHead(200, {
"Content-Type": "application/json",
"Access-Control-Allow-Origin": "*"
});
//.split creates an array with strings from the given url
//req.url -> gives everything that's right after the http://localhost:8080/ portion
var requested = req.url.split("/");
output.message = "Hello " + requested[2]; // 0 is empty, 1 is "get"
res.end(output);
});
希望有帮助。为
请求添加一个检查程序。url
基本上,以您自己的代码为例:
var server = http.createServer(function(req, res){
var output = {message: "Hello World!"};
var body = JSON.stringify(output);
res.writeHead(200, {
"Content-Type": "application/json",
"Access-Control-Allow-Origin": "*"
});
//.split creates an array with strings from the given url
//req.url -> gives everything that's right after the http://localhost:8080/ portion
var requested = req.url.split("/");
output.message = "Hello " + requested[2]; // 0 is empty, 1 is "get"
res.end(output);
});
希望有帮助。找到更好的方式require('url')。parse(req.url)找到更好的方式require('url')。parse(req.url)