Node.js 如何在mongoose中使用多于$group
] 在上面的json响应中 如何将PracticeValue、StatusValue分组为单个函数Node.js 如何在mongoose中使用多于$group,node.js,mongodb,mongoose,Node.js,Mongodb,Mongoose,] 在上面的json响应中 如何将PracticeValue、StatusValue分组为单个函数 [ { "_id":"56569bff5fa4f203c503c792", "Status":{ "StatusID":2, "StatusObjID":"56559aad5fa4f21ca8492277", "StatusValue":"Closed" }, "OwnerPractice":{ "P
[
{
"_id":"56569bff5fa4f203c503c792",
"Status":{
"StatusID":2,
"StatusObjID":"56559aad5fa4f21ca8492277",
"StatusValue":"Closed"
},
"OwnerPractice":{
"PracticeObjID":"56559aad5fa4f21ca8492291",
"PracticeValue":"CCC",
"PracticeID":3
},
"Name":"AA"
},
{
"_id":"56569bff5fa4f203c503c792",
"Status":{
"StatusID":2,
"StatusObjID":"56559aad5fa4f21ca8492277",
"StatusValue":"Open"
},
"OwnerPractice":{
"PracticeObjID":"56559aad5fa4f21ca8492292",
"PracticeValue":"K12",
"PracticeID":2
},
"Name":"BB"
}
以下代码仅用于对StatusValue进行分组,请帮助如何使用相同功能对练习值进行分组
[
{
"_id":"56569bff5fa4f203c503c792",
"Status":{
"StatusID":2,
"StatusObjID":"56559aad5fa4f21ca8492277",
"StatusValue":"Closed"
},
"OwnerPractice":{
"PracticeObjID":"56559aad5fa4f21ca8492291",
"PracticeValue":"CCC",
"PracticeID":3
},
"Name":"AA"
},
{
"_id":"56569bff5fa4f203c503c792",
"Status":{
"StatusID":2,
"StatusObjID":"56559aad5fa4f21ca8492277",
"StatusValue":"Open"
},
"OwnerPractice":{
"PracticeObjID":"56559aad5fa4f21ca8492292",
"PracticeValue":"K12",
"PracticeID":2
},
"Name":"BB"
}
我的回答是
Opp.aggregate([
{$group: {
_id: '$Status.StatusValue',
count: {$sum: 1}
}}
], function (err, result) {
res.send(result);
});
您可以按多个字段分组,如下所示:
[
{
"_id":"Deleted",
"count":0
},
{
"_id":"Open",
"count":1
},
{
"_id":"Closed",
"count":1
}
]
please help me, how to use more then $group function..
上面的代码没有得到预期的响应,计数值不正确我期待下面的响应格式,[{“Status”:[{“\u id”:“Deleted”,“count”:0},{“\u id”:“Open”,“count”:1},{“\u id”:“Closed”,“count”:1}]},{“Practice”:[{“\u id”:“K12”,“count”:31},{“\u id”:“HK”,“count”:12}]}]在这种情况下,您需要执行两个聚合查询