Node.js <;对象>;没有方法';CreateReadStream';
我想使用npm streaming-S3并将视频上传到S3。因此,我在node.js应用程序中使用以下代码Node.js <;对象>;没有方法';CreateReadStream';,node.js,amazon-s3,Node.js,Amazon S3,我想使用npm streaming-S3并将视频上传到S3。因此,我在node.js应用程序中使用以下代码 var streamingS3 = require('streaming-s3'), fs = require('fs'); var fStream = fs.CreateReadStream(__dirname + '/video.mp4'); var uploader = new streamingS3(fStream, {accessKeyId: process.env['A
var streamingS3 = require('streaming-s3'),
fs = require('fs');
var fStream = fs.CreateReadStream(__dirname + '/video.mp4');
var uploader = new streamingS3(fStream, {accessKeyId: process.env['AWS_ACCESS_KEY_ID'], secretAccessKey: secretAccessKey: process.env['AWS_SECRET_ACCESS_KEY']},
{
Bucket: 'example.streaming-s3.com',
Key: 'video.mp4',
ContentType: 'video/mp4'
}, function (err, resp, stats) {
if (err) return console.log('Upload error: ', e);
console.log('Upload stats: ', stats);
console.log('Upload successful: ', resp);
}
);
执行此代码后,我出现以下错误:
您的答案将很有价值。节点
fs
模块中没有方法CreateReadStream
。有(第一个字母必须小写):
var fStream=fs.createReadStream(uu dirname+'/video.mp4');