Objective c 在“中发送多个参数”;withParameters:“;呼叫
您好,我需要知道如何通过withParameters:method发送两个对象 这是我的密码:Objective c 在“中发送多个参数”;withParameters:“;呼叫,objective-c,parse-platform,Objective C,Parse Platform,您好,我需要知道如何通过withParameters:method发送两个对象 这是我的密码: NSDictionary *numberparam = [NSDictionary dictionaryWithObject:phoneNumber forKey:@"number"]; NSDictionary *messageparam = [NSDictionary dictionaryWithObject:message forKey:@"message"]; [P
NSDictionary *numberparam = [NSDictionary dictionaryWithObject:phoneNumber forKey:@"number"];
NSDictionary *messageparam = [NSDictionary dictionaryWithObject:message forKey:@"message"];
[PFCloud callFunctionInBackground:@"inviteWithTwilio" withParameters:numberparam messageparam block:^(id object, NSError *error) {
NSString *message1 = @"";
如果我从PFCloud调用中取出messageparam,一切都正常,但我需要包含它。如何做到这一点?您可以将它们放在字典中:
NSMutableDictionary * params = [NSMutableDictionary new];
params[@"number"] = phoneNumber;
params[@"message"] = message;
[PFCloud callFunctionInBackground:@"inviteWithTwilio" withParameters:params block:^(id object, NSError *error) {
NSString *message1 = @"";
}];
然后,在云计算中使用
var phoneNumber = request.number;
var message = request.message;
你可以把它们放在一本字典里:
NSMutableDictionary * params = [NSMutableDictionary new];
params[@"number"] = phoneNumber;
params[@"message"] = message;
[PFCloud callFunctionInBackground:@"inviteWithTwilio" withParameters:params block:^(id object, NSError *error) {
NSString *message1 = @"";
}];
然后,在云计算中使用
var phoneNumber = request.number;
var message = request.message;
不兼容的指针类型正在将“NSArray*”发送到“NSDictionary*”类型的参数。您是否看到更新,我的第一个原始数组答案是错误的。我试图在你看到它之前更新它!不兼容的指针类型正在将“NSArray*”发送到“NSDictionary*”类型的参数。您是否看到更新,我的第一个原始数组答案是错误的。我试图在你看到它之前更新它!