Opencv 2.4.3如何将IPL_DEPTH_8U转换为IPL_DEPTH_32F？

始终失败，表示“未知函数中的断言失败（src.size==dst.size&&dst.type（）==CV_8UC（src.channels（））”

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我搜索了很多方法，但似乎没有一种有效？

这里有一个简单的函数，可以将任何

IplImage

转换为32位浮点

char* filename1="1.bmp";  
IplImage* greyLeftImg= cvLoadImage(filename1,0);
char* filename2="2.bmp";
IplImage* greyRightImg= cvLoadImage(filename2,0); 

IplImage* greyLeftImg32=cvCreateImage(cvSize(width,height),32,greyLeftImg->nChannels);//IPL_DEPTH_32F 
IplImage* greyRightImg32=cvCreateImage(cvSize(width,height),32,greyRightImg->nChannels);

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将opencv中的任何灰度8位或16位uint图像转换为32位浮动类型的简单步骤如下

IplImage* img8u = cvLoadImage(filename1,0);

IplImage* img32f = convert_to_float32(img8u);

cvShowImage("float image",img32f); //Image will not be shown correctly
cvWaitKey(0);

cvScale(img32f, img32f, 1.0/255.0);

cvShowImage("float image normalized",img32f); //Image will be shown correctly now 
cvWaitKey(0);

希望这是一个简单的方法

IplImage* img8u = cvLoadImage(filename1,0);

IplImage* img32f = convert_to_float32(img8u);

cvShowImage("float image",img32f); //Image will not be shown correctly
cvWaitKey(0);

cvScale(img32f, img32f, 1.0/255.0);

cvShowImage("float image normalized",img32f); //Image will be shown correctly now 
cvWaitKey(0);

IplImage* img = cvLoadImage( "E:\\Work_DataBase\\earth.jpg",0);
IplImage* out = cvCreateImage( cvGetSize(img), IPL_DEPTH_32F, img->nChannels);

double min,max;

cvMinMaxLoc(img,&min,&max);

// Remember values of the floating point image are in the range of 0 to 1, which u 
// can't visualize by cvShowImage().......
cvCvtScale(img,out,1/ max,0);