Oracle 打印嵌套表中的引号

Oracle 打印嵌套表中的引号,oracle,plsql,oracle10g,Oracle,Plsql,Oracle10g,正在尝试完成以下操作: CREATE OR REPLACE PROCEDURE POPULATE_ACTOR_QUOTES (id_actor char) AS CURSOR quote_recs IS SELECT m.title, m.year, r.roleName, q.quotechar from quote q, role r,

正在尝试完成以下操作:

    CREATE OR REPLACE 
PROCEDURE POPULATE_ACTOR_QUOTES (id_actor char)
AS
   CURSOR quote_recs IS
      SELECT m.title, 
             m.year, 
             r.roleName,
             q.quotechar 
        from quote q, 
             role r, 
             rolequote rq,  
             actor a, 
             movie m
       where rq.quoteID = q.quoteID
         AND rq.roleID = r.roleID
         AND r.actorID = a.actorID
         AND r.movieID = m.movieID
         AND a.actorID = id_actor;
BEGIN
   FOR row IN quote_recs 
   LOOP
      INSERT INTO table(
      SELECT quotes
        FROM actor_quotes aq
       WHERE aq.actorId = id_actor)
      VALUES(
         ACTOR_QUOTE_TYPE(row.title, row.year, row.roleName, row.quotechar)
      );
   end loop;
END POPULATE_ACTOR_QUOTES;
/
创建一个名为PRINT_ACTOR_QUOTES的PL/SQL过程,方法是使用单个参数修改过程POPULATE_ACTOR_QUOTES:从ACTOR表中打印出与ACTORID对应的firstname和lastname属性ACTORID是过程参数,并从嵌套的QUOTES表中打印出所有报价信息

这就是我所创造的:

CREATE OR REPLACE PROCEDURE PRINT_ACTOR_QUOTES (id_actor char)
AS
CURSOR quote_recs IS
SELECT a.firstName,a.lastName, m.title, m.year, r.roleName ,q.quotechar from quote q, role r,   
rolequote rq, actor a, movie m
where
rq.quoteID = q.quoteID
AND
rq.roleID = r.roleID
 AND
r.actorID = a.actorID
AND
r.movieID = m.movieID
AND
 a.actorID = id_actor;
BEGIN
FOR row IN quote_recs
LOOP
  DBMS_OUTPUT.PUT_LINE( row.firstName || ' ' || row.lastName );

END LOOP;

END PRINT_ACTOR_QUOTES;
/ 
输出

SQL> EXECUTE PRINT_ACTOR_QUOTES ('00070')

Dustin                   Hoffman
需要创建如下输出:

杰夫·戈德布鲁姆

|Title           | Year |       Role     |                Quote                               |
----------------------------------------------------------------------------------------------
|THE FLY         |1986  |SETH BRUNDLE    | “I’m free and you don’t like it’’ |
|INDEPENDENCE DAY| 1996 | DAVID LEVINSON | “I’ve given it a virus”           |
我有第一个名字和第二个名字-需要嵌套引号表中的信息

需要帮助

我得到了下面的select查询,它从嵌套的引号中调出所需的信息-只需要将它添加到-PROCEDURE PRINT\u ACTOR\u quotes中

SELECT REC.*
  FROM ACTOR_QUOTES A,TABLE(A.QUOTES) REC
  WHERE ACTORID = ('00070')

我可能错过了什么

CREATE OR REPLACE PROCEDURE PRINT_ACTOR_QUOTES (id_actor char)
AS
CURSOR quote_recs IS
SELECT a.firstName,a.lastName, m.title, m.year, r.roleName ,q.quotechar from quote q, role r,   
rolequote rq, actor a, movie m
where
rq.quoteID = q.quoteID
AND
rq.roleID = r.roleID
 AND
r.actorID = a.actorID
AND
r.movieID = m.movieID
AND
 a.actorID = id_actor;

is_first boolean := true;

BEGIN
FOR row IN quote_recs
LOOP
if is_first then
  DBMS_OUTPUT.PUT_LINE( row.firstName || ' ' || row.lastName );
  DBMS_OUTPUT.PUT_LINE( 'Title   | Year |    Role     |     Quote  ');
  is_first := false;
end if;

  DBMS_OUTPUT.PUT_LINE( row.title|| ' ' || row.year|| ' ' || row.role || ' ' || row.quotechar );

END LOOP;

END PRINT_ACTOR_QUOTES;
/ 

您的问题不清楚,当您尝试循环此查询结果时会发生什么情况?我创建了一个名为和姓为的输出,但在DBMS|u OUTPUT.PUT_LINE row.firstName | | | row.lastName下添加表时遇到问题;显示标题、年份、角色、报价