如何使用最新记录消除oracle中的价值

输出 这是我试图获取最新记录的代码，但它对我不起作用。我会附上一张图片以便更好地理解。你能找出那个问题吗

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您正在按ID进行分区，以便获得结果中的所有行。 我想应该是这样

    select *
    from (select
       id,NPCI_REFMSGID,TO_CHAR (created_date, 'dd.mm.rrrr hh24:mi:ss.ff3')AS created_Date, 
      rank() over (partition by ID order by TO_CHAR (created_date, 'dd.mm.rrrr hh24:mi:ss.ff3') desc) r
      from emnd_tblemandate_mst
      --where end_enrollment_date is null
    )
    where r = 1 AND NPCI_REFMSGID='1ea345bc63644b53a88076040ef979e3'

然后，您只会获得特定NPCI_REFMSGID的最新记录

    select *
    from (select
       id,NPCI_REFMSGID,TO_CHAR (created_date, 'dd.mm.rrrr hh24:mi:ss.ff3')AS created_Date, 
      rank() over (partition by ID order by TO_CHAR (created_date, 'dd.mm.rrrr hh24:mi:ss.ff3') desc) r
      from emnd_tblemandate_mst
      --where end_enrollment_date is null
    )
    where r = 1 AND NPCI_REFMSGID='1ea345bc63644b53a88076040ef979e3'

select *
from (select id 
           , NPCI_REFMSGID
           , TO_CHAR (created_date, 'dd.mm.rrrr hh24:mi:ss.ff3')AS created_Date
           , rank() over (partition by NPCI_REFMSGID order by created_date desc) r
      from   emnd_tblemandate_mst
)
where r = 1 
AND   NPCI_REFMSGID = '1ea345bc63644b53a88076040ef979e3'