Oracle xml的递归层次查询

要使用dynatree（），我希望结果是下面的xml格式，但结果不是我想要的。 动态树需要第二个来组织树

有人能帮我吗

SELECT 
  XMLELEMENT("div",xmlattributes('tree' AS "id"),
       (SELECT DBMS_XMLGEN.getXMLType(
     DBMS_XMLGEN.newContextFromHierarchy('
        SELECT LEVEL,
           case
             when CONNECT_BY_ISLEAF = 0 then
              XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename))
             when CONNECT_BY_ISLEAF = 1 then
              XMLELEMENT("li", xmlattributes(empno AS "id"), ename)
           end
          FROM emp
         START WITH mgr is null
        CONNECT BY PRIOR empno = mgr '
        )
       ) FROM DUAL
      )) XMLDOC  
 FROM DUAL;

当前结果

<div id="tree"><ul>
  <li id="7839">KING</li>
  <ul>
    <li id="7566">JONES</li>
    <ul>
      <li id="7788">SCOTT</li>
      <li id="7876">ADAMS</li>
    </ul>
    <ul>
      <li id="7902">FORD</li>
      <li id="7369">SMITH</li>
    </ul>
  </ul>
  <ul>
    <li id="7698">BLAKE</li>
    <li id="7499">ALLEN</li>
    <li id="7521">WARD</li>
    <li id="7654">MARTIN</li>
    <li id="7844">TURNER</li>
    <li id="7900">JAMES</li>
  </ul>
  <ul>
    <li id="7782">CLARK</li>
    <li id="7934">MILLER</li>
  </ul>
</ul>
</div>

---

嗨，把你的案例逻辑颠倒过来，我测试了一下，发现它在工作

SELECT 
--  XMLELEMENT("ul",null,
       (SELECT DBMS_XMLGEN.getXMLType(
     DBMS_XMLGEN.newContextFromHierarchy('
        SELECT LEVEL,
           case
             when CONNECT_BY_ISLEAF = 1 then
              XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename))
             when CONNECT_BY_ISLEAF = 0 then
              XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename), null)
           end
          FROM emp
         START WITH mgr is null
        CONNECT BY PRIOR empno = mgr '
        )
       ) FROM DUAL
      )
--      ) XMLDOC  
 FROM DUAL;

请检查您需要的输出是否与问题中指定的完全一致

根据我的说法，输出应如下所示：

<ul>
  <li id="7839">KING</li>
  <ul>
    <li id="7566">JONES</li>
    <ul>
      <li id="7788">SCOTT</li>
      <ul>
        <li id="7876">ADAMS</li>
      </ul>
    </ul>
    <ul>
      <li id="7902">FORD</li>
      <ul>
        <li id="7369">SMITH</li>
      </ul>
    </ul>
  </ul>
  <ul>
    <li id="7698">BLAKE</li>
    <ul>
      <li id="7499">ALLEN</li>
    </ul>
    <ul>
      <li id="7521">WARD</li>
    </ul>
    <ul>
      <li id="7654">MARTIN</li>
    </ul>
    <ul>
      <li id="7844">TURNER</li>
    </ul>
    <ul>
      <li id="7900">JAMES</li>
    </ul>
  </ul>
  <ul>
    <li id="7782">CLARK</li>
    <ul>
      <li id="7934">MILLER</li>
    </ul>
  </ul>
</ul>

国王

琼斯

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亚当斯



福特

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布莱克

艾伦


病房


马丁


特纳


詹姆斯



克拉克

米勒

---

检查并更新您是否需要这些数据。

您拥有的表格数据是什么…？，即表格名称…数据是什么，…显示可用的数据…添加了表格创建脚本和数据插入脚本。您好，请确认您的问题是否已解决。

SELECT 
--  XMLELEMENT("ul",null,
       (SELECT DBMS_XMLGEN.getXMLType(
     DBMS_XMLGEN.newContextFromHierarchy('
        SELECT LEVEL,
           case
             when CONNECT_BY_ISLEAF = 1 then
              XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename))
             when CONNECT_BY_ISLEAF = 0 then
              XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename), null)
           end
          FROM emp
         START WITH mgr is null
        CONNECT BY PRIOR empno = mgr '
        )
       ) FROM DUAL
      )
--      ) XMLDOC  
 FROM DUAL;

<ul>
  <li id="7839">KING</li>
  <ul>
    <li id="7566">JONES</li>
    <ul>
      <li id="7788">SCOTT</li>
      <ul>
        <li id="7876">ADAMS</li>
      </ul>
    </ul>
    <ul>
      <li id="7902">FORD</li>
      <ul>
        <li id="7369">SMITH</li>
      </ul>
    </ul>
  </ul>
  <ul>
    <li id="7698">BLAKE</li>
    <ul>
      <li id="7499">ALLEN</li>
    </ul>
    <ul>
      <li id="7521">WARD</li>
    </ul>
    <ul>
      <li id="7654">MARTIN</li>
    </ul>
    <ul>
      <li id="7844">TURNER</li>
    </ul>
    <ul>
      <li id="7900">JAMES</li>
    </ul>
  </ul>
  <ul>
    <li id="7782">CLARK</li>
    <ul>
      <li id="7934">MILLER</li>
    </ul>
  </ul>
</ul>