Oracle选择最近日期记录

我试图根据日期字段查找最近的记录。当我在where子句中设置latest=1时，我得到一个错误。如果可能的话，请帮忙。日期是我排序依据的字段。我尝试了latest=1和latest='1'

SELECT 
STAFF_ID,
SITE_ID,
PAY_LEVEL,
ROW_NUMBER() OVER (PARTITION BY STAFF_ID ORDER BY DATE DESC) latest

 FROM OWNER.TABLE
WHERE   END_ENROLLMENT_DATE is null 
AND latest = 1

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我想我应该试着和MAX一起做这样的事情：

SELECT staff_id, max( date ) from owner.table group by staff_id

然后在其他列中链接：

select staff_id, site_id, pay_level, latest
from owner.table, 
(   SELECT staff_id, max( date ) latest from owner.table group by staff_id ) m
where m.staff_id = staff_id
and m.latest = date

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假设员工id+日期来自英国，这是另一种方法：

SELECT STAFF_ID, SITE_ID, PAY_LEVEL
  FROM TABLE t
  WHERE END_ENROLLMENT_DATE is null
    AND DATE = (SELECT MAX(DATE)
                  FROM TABLE
                  WHERE staff_id = t.staff_id
                    AND DATE <= SYSDATE)

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由于select语句的错误，您不能在WHERE子句中使用select列表中的别名

此外，不能在WHERE子句中使用OVER子句-可以在select list或ORDER BY子句中使用该子句指定分析函数。引证

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…你可能不想要最新的记录，但最新的记录：date排名帮助很大，谢谢，因为我必须加入多个表，不想在子选择中重复这些加入。

select *
from (select
  staff_id, site_id, pay_level, date, 
  max(date) over (partition by staff_id) max_date
  from owner.table
  where end_enrollment_date is null
)
where date = max_date

select *
from (select
  staff_id, site_id, pay_level, date, 
  rank() over (partition by staff_id order by date desc) r
  from owner.table
  where end_enrollment_date is null
)
where r = 1