Oracle10g 甲骨文；ORA-00904:：无效标识符"；=Oracle 10 G上的粗体SQL命令出错

shift

是保留字。您需要以不同的方式命名该列

永远不要将日期存储为

char

或

varchar

列！ 此外，名称

date

也不是一个很好的选择。除了作为保留字外，它并没有记录该列的内容。“开始日期”、“结束日期”、“加入日期”、“到期日期”

使用

char

datatype几乎总是无法实现您想要的功能，因为它的值被填充到定义的长度。我很确定你想要的是

varchar

（或者

varchar2

）

如果您的id（

cor_id

，…）实际上是数字，则应将这些列定义为

number

（或

integer

）

因此，所讨论的表格至少应如下所示：

create table Coordinator(
cor_id char(6) primary key,
cor_name varchar(10) not null,
contact_no char(12),
address varchar(50));

create table Student(
student_id char(6) primary key,
name varchar(10) not null,
department char(20),
grade char(6),
percentage smallint,
contact_no char(12),
address varchar(50));

create table Criteria(
crt_id char(6) primary key,
min_cutoff smallint);

create table Company(
cmp_id char(6) primary key,
crt_id char(6),
cmp_name varchar(25) not null,
grade char(6),
package int,
contact_no char(12),
address varchar(50),
foreign key (crt_id) references Criteria(crt_id));

**create table Coordinate_with(
cor_id char(6),
cmp_id char(6),
date char(10),
shift varchar(10),
primary key (cor_id,cmp_id),
foreign key (cor_id) references Coordinator(cor_id),
foreign key (cmp_id) references Company(cmp_id));**

create table Placed_in(
cmp_id char(6),
student_id char(6),
primary key (cmp_id,student_id),
foreign key (comp_id) references Company,
foreign key (student_id) references Student);

create table Criteria_Branch(
crt_id char(6),
branch_allowed varchar(20),
primary key (crt_id, branch_allowed),
foreign key (crt_id) references Criteria(crt_id);

create table Coordinate_with
(
  cor_id char(6),
  cmp_id char(6),
  start_date date,      -- or whatever name describes better what kind of date that is.
  shifted varchar(10),  -- the name is just a suggestion, use what best describes this column
  primary key (cor_id,cmp_id),
  foreign key (cor_id) references Coordinator(cor_id),
  foreign key (cmp_id) references Company(cmp_id)
);