Php 自动刷新ajax隐藏类bot not id

好的，我有一个functions.php来处理一些函数

一个是

函数注释功能条

此函数在每个帖子评论的底部输出

No likes·Like·Report

我有一个sendlike.php来处理mysql数据

    <?php
//include db configuration file
include_once("config.php");
//Include functions
include_once("functions.php");


// For practice
    $uid_fk = 1;

//check $_POST["content_txt"] is not empty
if(isset($_GET["like"]) && strlen($_GET["like"])>0) 
{   

    //Add IP, date. Set the Foreign key
    $ip = $_SERVER['REMOTE_ADDR'];
    $date = date("Y-m-d H:i:s");
    $comment_id_fk = $_GET["like"]; // '".$comment_id_fk."', What comment has been liked?

    // $_SESSION["user_id"]  '".$uid_fk."', What user has liked it? Get the users uid

    // Insert sanitize string in record
    $insert_row = $mysqli->query("INSERT INTO comment_likes (comment_id_fk, uid_fk,date,ip)
        VALUES('".$comment_id_fk."','".$uid_fk."','".$date."','".$ip."')");

    if($insert_row)
    {
        //Count the amount of likes again
        $count_likes=$mysqli->query("SELECT COUNT(*) as TOTAL_COMMENT_LIKES FROM `comment_likes` 
        WHERE comment_id_fk='".$comment_id_fk."'");
        $row_array=$count_likes->fetch_array(MYSQLI_ASSOC);

       $mysqli->close(); //close db connection
// header('Location: ' . $_SERVER['HTTP_REFERER']); //ADD
    }else{

        //header('HTTP/1.1 500 '.mysql_error()); //display sql errors.. must not output sql errors in live mode.
        header('HTTP/1.1 500 Looks like mysql error, could not insert record!');
        exit();
    }

}
elseif(isset($_GET["delike"]) && strlen($_GET["delike"])>0 && is_numeric($_GET["delike"]))
{   //do we have a delete request? $_POST["recordToDelete"]

    //sanitize post value, PHP filter FILTER_SANITIZE_NUMBER_INT removes all characters except digits, plus and minus sign.
    $idToDelete = filter_var($_GET["delike"],FILTER_SANITIZE_NUMBER_INT); 

    //try deleting record using the record ID we received from POST
    $delete_row = $mysqli->query("DELETE FROM comment_likes WHERE comment_id_fk='".$idToDelete."' AND uid_fk ='".$uid_fk."'"); //uid_fk is $_SESSION[user_id] actually

    if(!$delete_row)
    {    
        //If mysql delete query was unsuccessful, output error 
        header('HTTP/1.1 500 Could not delete record!');
        exit();
    }
    $mysqli->close(); //close db connection
  //  header('Location: ' . $_SERVER['HTTP_REFERER']); //ADD
}
else
{
    //Output error
    header('HTTP/1.1 500 Error occurred, Could not process request!');
    exit();
}
?>

插入到数据库可以工作，但不能自动刷新。它还使用class=“clickable”隐藏和淡入所有注释。有人能帮我吗

似乎我还需要在Ajax函数中隐藏href id。但我真的不知道怎么做。试图使用#comment_id，但运气不佳。

将ajax更改为：

<script type="text/javascript">
            $(document).on('click', '.clickable', function(e) {
                e.preventDefault(); 
                var action =  $(this).html();
                var comment_id = $(this).attr('id');
                if(action == 'Like')
                {
                    var data ={like:comment_id};
                    var status="Unlike";

                }
                else
                {
                    var data ={delike:comment_id};
                    var status = "Like";
                }
                $.ajax({
                    type: "GET",
                    url: "sendlike.php",
                    data:data,
                    dataType: "text",
                    success: function(response){ 
                    $(".txtHint_"+comment_id).hide();
                    $(".txtHint_"+comment_id).html("");
                    $(".txtHint_"+comment_id).append(response).fadeIn();
                    },
                 error:function (xhr, ajaxOptions, thrownError){
                //On error, we alert user
                alert(thrownError);
                             }

            });
            });
 </script>

$（文档）.on（'click'，'clickable'，函数（e）{
e、 预防默认值（）；
var action=$（this.html（）；
var comment_id=$（this.attr（'id'）；
如果（动作=='Like'）
{
var data={like:comment_id}；
var status=“不像”；
}
其他的
{
var data={delike:comment_id}；
var status=“Like”；
}
$.ajax({
键入：“获取”，
url:“sendlike.php”，
数据：数据，
数据类型：“文本”，
成功：功能（响应）{
$（“.txtHint_uu”+注释_id）.hide（）；
$（“.txtHint_uu”+comment_id）.html（“”）；
$（“.txtHint_u”+注释_id）.append（response.fadeIn（）；
},
错误：函数（xhr、ajaxOptions、thrownError）{
//出现错误时，我们会提醒用户
警报（thrownError）；
}
});
});

---

并从@EhsanT获得关于sendlike.php的建议首先，您必须隐藏并淡出相应id的注释，而不是使用

可点击的
类的所有注释。其次，您可以在
sendlike.php
文件中生成有关注释（喜欢或不喜欢）状态的
HTML
代码，并将其回显。然后在
axaj
中分析响应，并在成功响应后显示正确的链接。
  echo '<p id="txtHint"><small>' . $how_many .' <a href="#" class="clickable" id="'.$comment_id .'">Like</a> · <a href="">Report</a>'.$owner.'</small></p>';
 }
 else 
 {
     echo '<p id="txtHint"><small>' . $how_many .' <a href="#" class="clickable" id="'.$comment_id .'">Unlike</a> · <a href="">Report</a>'.$owner.'</small></p>';
 } 

<script type="text/javascript">
            $(document).on('click', '.clickable', function(e) {
                e.preventDefault(); 
                var action =  $(this).html();
                var comment_id = $(this).attr('id');
                if(action == 'Like')
                {
                    var data ={like:comment_id};
                    var status="Unlike";

                }
                else
                {
                    var data ={delike:comment_id};
                    var status = "Like";
                }
                $.ajax({
                    type: "GET",
                    url: "sendlike.php",
                    data:data,
                    dataType: "text",
                    success: function(response){ 
                    $(".txtHint_"+comment_id).hide();
                    $(".txtHint_"+comment_id).html("");
                    $(".txtHint_"+comment_id).append(response).fadeIn();
                    },
                 error:function (xhr, ajaxOptions, thrownError){
                //On error, we alert user
                alert(thrownError);
                             }

            });
            });
 </script>