Php 引导和codeIgniter数据显示在表中

我正在从数据库中提取数据。我想在表中显示该数据，但我想在一行中显示5列。之后，它将从新行开始。请帮忙

在第一个值中添加，在第五个值中添加。它将运行

<table class="table table-bordered table-hover">
    <?php foreach ($pin_data as $pin) {
      ?>
      <tr>
        <td><?php  echo $pin->location;?> <?php  echo $pin->pincode;?></td>
      </tr>
      <?php
    } ?>

  </table>

希望这将帮助您：

这样做：

---

您可以使用模数运算符和计数器：

<table class="table table-bordered table-hover">
    <?php foreach ($pin_data as $pin) { ?>
      <tr>

         /*change your column name as according to you*/

         <td><?php  echo $pin->location;?></td> 
         <td><?php  echo $pin->pincode;?></td>
         <td><?php  echo $pin->location;?></td> 
         <td><?php  echo $pin->pincode;?></td>
         <td><?php  echo $pin->location;?></td> 
      </tr>
      <?php } ?>
</table>

---

再读一遍我的问题。

<table class="table table-bordered table-hover">
    <?php foreach ($pin_data as $pin) { ?>
      <tr>

         /*change your column name as according to you*/

         <td><?php  echo $pin->location;?></td> 
         <td><?php  echo $pin->pincode;?></td>
         <td><?php  echo $pin->location;?></td> 
         <td><?php  echo $pin->pincode;?></td>
         <td><?php  echo $pin->location;?></td> 
      </tr>
      <?php } ?>
</table>

<table class="table table-bordered table-hover">
   <tr> <!-- start initial row -->
    <? $counter = 1; 
       foreach ($pin_data as $pin):?>
          <td>
              <?= $pin->location;?> <?= $pin->pincode;?>
          </td>
       <?if($counter % 5 == 0):?> //if $counter is a multiple of 5, close the current row and start an new one 
       </tr> 
       <tr>  
       <?endif;?>
       <? $counter++;?>
       <?endforeach;?>
</table>