Php Symfony3序列化程序-如何从点字符串中分离值并合并到一个数组列中

我以给定的形式从http请求中获取数据

{
  "start_date": "2017-03-13",
  "end_date": "2017-03-19",
  "visitors_total": 2555,
  "views_total": 2553,
  "visitors_country.france": 100,
  "visitors_country.germany": 532,
  "visitors_country.poland": 32,
  "views_country.france": 110,
  "views_country.germany": 821,
  "views_country.poland": 312,
}

列的条令实体定义

"start_date" => datetime
"end_date" => datetime
"visitors_total" => int
"views_total" => int
"visitors_country" => array
"views_country => array

对于访客\国家/地区和视图\国家/地区，数组键/值用点分隔。这些点分隔的值

"views_country.france": 110,
"views_country.germany": 821,
"views_country.poland": 312,

应该是

'view_country' => array(
   'france'=> 110,
   'germany'=> 821,
   'poland'=> 312,
);

我正在使用Symfony serialize组件对请求的数据进行序列化，并且在对数据进行反规范化时遇到问题

我做了这样的事

class ArrayDotNormalizer implements DenormalizerInterface
{

    /**
     * {@inheritdoc}
     *

     */
    public function denormalize($data, $class, $format = null, array $context = array())
    {
     // Actually, this function applies to each column of requested data ,
    //but how to  separate values by dot and join them in one array and store as array json in db ?
    }

    /**
     * {@inheritdoc}
     */
    public function supportsDenormalization($data, $type, $format = null)
    {

        return strpos($data, '.') !== false;
    }

}

有什么办法解决这个问题吗？

试试这个：

class ArrayDotNormalizer extends ObjectNormalizer
{
    /**
     * {@inheritdoc}
     */
    protected function setAttributeValue($object, $attribute, $value, $format = null, array $context = [])
    {
        if (strpos($attribute, '.') !== false) {
            list($attribute, $country) = explode('.', $attribute);
            $currentValue = (array) $this->propertyAccessor->getValue($object, $attribute);
            $value = array_replace($currentValue, [$country => $value]);
        }

        return parent::setAttributeValue($object, $attribute, $value, $format, $context);
    }
}

并在序列化程序中使用此规范化程序：

 $serializer = new Serializer([new ArrayDotNormalizer()], [new JsonEncoder()]);

结果:

---

来自http的数据是json吗？如果是这样，那么解码json将返回数组，然后尝试使用带（点）的explode选项使其成为所需的数组结构