Php 验证拉威尔误差
我正在尝试在Lumen中使用Php 验证拉威尔误差,php,laravel,lumen,Php,Laravel,Lumen,我正在尝试在Lumen中使用$this->validate助手。但是,对于请求,我需要执行$request->json()->all(),而不是$request->all(),这只是因为在使用后者时,我无法获得确切的参数及其值(即使字段有值,它仍会将其标记为失败) $request->json()->all()输出: array:6 [ "username" => "" "first_name" => "asaas" "last_name" => "" "ema
$this->validate
助手。但是,对于请求,我需要执行$request->json()->all()
,而不是$request->all()
,这只是因为在使用后者时,我无法获得确切的参数及其值(即使字段有值,它仍会将其标记为失败)
$request->json()->all()输出:
array:6 [
"username" => ""
"first_name" => "asaas"
"last_name" => ""
"email_address" => ""
"password" => ""
"password_confirmation" => ""
]
array:1 [
"{"username":"","first_name":"asaas","last_name":"","email_address":"","password":"","password_confirmation":""}" => ""
]
$request->all()输出:
array:6 [
"username" => ""
"first_name" => "asaas"
"last_name" => ""
"email_address" => ""
"password" => ""
"password_confirmation" => ""
]
array:1 [
"{"username":"","first_name":"asaas","last_name":"","email_address":"","password":"","password_confirmation":""}" => ""
]
现在,当我在助手上传递$request->json()->all()
时:
$this->validate($request->json()->all(), [
'username' => 'required|min:2|max:20',
'first_name' => 'required|max:50',
'last_name' => 'required|max:50',
'email_address' => 'required|email',
'password' => 'required',
]);
它将抛出一个错误:
类型错误:参数1传递给
Laravel\Lumen\Routing\Controller::validate()必须是的实例
Illumb\Http\请求,给定数组,在中调用
正如我所预料的,因为应该传递
$request
,而不是传递带有json()->all()的请求。如何处理错误?像这样使用验证器
use Illuminate\Support\Facades\Validator;
$validator = Validator::make($request->json()->all(), [
'username' => 'required|min:2|max:20',
'first_name' => 'required|max:50',
'last_name' => 'required|max:50',
'email_address' => 'required|email',
'password' => 'required',
]);
然后处理验证检查
if ($validator->fails()) {
return response()->json($validator->errors(), 422);
}
或
为什么必须使用$request->json()->all()
?不能将数组传递给validate,它必须是请求对象。