Php jquery自动完成组合查询

我有一个php/mysql站点正在运行，它基本上跟踪应该在确定时间内运行的任务。 我被要求对用户进行分析，这样其中一个就看不到另一个的项目。 到目前为止还不错，差不多完成了，一般来说，通过创建一个角色表和用户限制条件中的查询来解决它

我遇到了一个我没想到会发生的问题。在我的搜索/筛选表单中，我有一个使用DB连接的jquery自动完成文本区域，因此用户可以按任务名称进行搜索。 现在，当我（仅）更改获取任务名称的查询时，自动完成不再起作用

该查询很好，它返回的结果与以前的结果相同，只有很少的结果，因为新的条件，没有其他更改

工作自动完成：

html:

php:

不使用此php：

<?php
include ('../connect-db.php');
include ('session_check.php');
$q = trim(strip_tags($_GET['term']));

$qstring = "SELECT t.name as value 
FROM CO_SERV AS s, CO_APP AS ap, CO_USERS AS u, CO_GROUPS AS g, CO_GROUP_ROLES AS gr, TASKS AS t
WHERE name LIKE '%".$q."%' 
AND g.ID_G = u.ID_G
AND s.ID = gr.ID_S
AND g.ID_G = gr.ID_G
AND ap.ID_AP = gr.ID_AP
AND u.ID_U = '3' //example id user to test it will be a post
AND t.servico = s.ID
AND ap.ID_AP = t.app
AND t.public = '1'
AND t.ative = '1'
AND gr.ative = '1'";
$result = mysql_query($qstring);

while ($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
  $row['value'] = iconv('ISO-8859-1', 'UTF-8', $row['value']);
  $row_set[] = $row;
}
echo json_encode($row_set);
?>

此查询很好，返回的结果与其他查询相同，唯一的区别是它仅限于用户权限 看不出有什么问题

感谢您的任何帮助：）

致意

---

Gonçalo

检查浏览器控制台的“网络”选项卡，并确保（i）auto complete正在请求search.php（ii）search.php生成结果（iii）结果是有效的JSONIn Firebug控制台响应和HTML显示为“null”，请忘记它！！问题是include（'../connectdb.php'）；好连接到生产数据库，我正在开发中构建东西，所以生产中仍然不存在表！！哼！所以没问题，一切正常。谢谢Salman，有时候花点时间调试是值得的

$( "#task" ).autocomplete({
  source: "includes/search.php",
  minLength: 2,
  select: function( event, ui ) {
  log( ui.item ? "" + ui.item.value :
  "Nothing selected, input was " + this.value );}
});

<?php
include ('../connect-db.php');

$q = trim(strip_tags($_GET['term']));

$qstring = "SELECT name as value FROM TASKS WHERE name LIKE '%".$q."%' AND public='1' AND active='1'";
$result = mysql_query($qstring);

while ($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
  $row['value'] = iconv('ISO-8859-1', 'UTF-8', $row['value']);
  $row_set[] = $row;
}
echo json_encode($row_set);
?>

<?php
include ('../connect-db.php');
include ('session_check.php');
$q = trim(strip_tags($_GET['term']));

$qstring = "SELECT t.name as value 
FROM CO_SERV AS s, CO_APP AS ap, CO_USERS AS u, CO_GROUPS AS g, CO_GROUP_ROLES AS gr, TASKS AS t
WHERE name LIKE '%".$q."%' 
AND g.ID_G = u.ID_G
AND s.ID = gr.ID_S
AND g.ID_G = gr.ID_G
AND ap.ID_AP = gr.ID_AP
AND u.ID_U = '3' //example id user to test it will be a post
AND t.servico = s.ID
AND ap.ID_AP = t.app
AND t.public = '1'
AND t.ative = '1'
AND gr.ative = '1'";
$result = mysql_query($qstring);

while ($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
  $row['value'] = iconv('ISO-8859-1', 'UTF-8', $row['value']);
  $row_set[] = $row;
}
echo json_encode($row_set);
?>