Php 从AS中选择并加入Laravel
如何在Laravel上执行此查询Php 从AS中选择并加入Laravel,php,mysql,laravel,Php,Mysql,Laravel,如何在Laravel上执行此查询 SELECT * FROM conversion t1 JOIN (SELECT report_id, MAX(id) id FROM conversion GROUP BY report_id ) AS t2 ON t1.id = t2.id AND t1.report_id = t2.report_id 我已经在拉威尔的纪录片里看过了,但什么也没找到 我已经在SQL中尝试并正在工作,
SELECT *
FROM conversion t1
JOIN (SELECT report_id, MAX(id) id
FROM conversion
GROUP BY report_id ) AS t2
ON t1.id = t2.id AND t1.report_id = t2.report_id
我已经在拉威尔的纪录片里看过了,但什么也没找到
我已经在SQL中尝试并正在工作,但我不知道如何在Laravel中执行此查询
请帮助解决此问题,谢谢。现在没有我的IDE,但它应该是这样工作的:
$results = DB::select(DB::raw ('SELECT *
FROM conversion t1
JOIN (SELECT report_id, MAX(id) id
FROM conversion
GROUP BY report_id ) AS t2
ON t1.id = t2.id AND t1.report_id = t2.report_id'));
我现在没有IDE,但它应该是这样工作的:
$results = DB::select(DB::raw ('SELECT *
FROM conversion t1
JOIN (SELECT report_id, MAX(id) id
FROM conversion
GROUP BY report_id ) AS t2
ON t1.id = t2.id AND t1.report_id = t2.report_id'));
我认为这是你问题的正确答案:
$subQuery = \DB::table('conversion')
->selectRaw('report_id, MAX(id) id')
->groupBy('report_id')
->toSql();
$data = \DB::table('conversion t1')
->join(\DB::raw('(' . $subQuery . ') as t2'), function ($join) {
$join->on('t1.id', 't2.id')
->on('t1.report_id', 't2.report_id');
}, null, null, '')
->get();
如果您想检查这个查询,最后可以使用->toSql()
而不是->get()
。
输出为:
select *
from `conversion t1`
join (
select report_id, MAX(id) as id
from `conversion`
group by `report_id`
) as t2
on `t1`.`id` = `t2`.`id`
and `t1`.`report_id` = `t2`.`report_id`
我认为这是你问题的正确答案:
$subQuery = \DB::table('conversion')
->selectRaw('report_id, MAX(id) id')
->groupBy('report_id')
->toSql();
$data = \DB::table('conversion t1')
->join(\DB::raw('(' . $subQuery . ') as t2'), function ($join) {
$join->on('t1.id', 't2.id')
->on('t1.report_id', 't2.report_id');
}, null, null, '')
->get();
如果您想检查这个查询,最后可以使用->toSql()
而不是->get()
。
输出为:
select *
from `conversion t1`
join (
select report_id, MAX(id) as id
from `conversion`
group by `report_id`
) as t2
on `t1`.`id` = `t2`.`id`
and `t1`.`report_id` = `t2`.`report_id`