警告：非法字符串偏移量'；位置'；在第57行的C:\xampp\htdocs\PMSS\login.php中

这是我的login.php

<?php

//load and connect to MySQL database stuff
require("config.inc.php");

if (!empty($_POST)) {

    if(empty($_POST['username']) || empty($_POST['password'])) {

        $response["success"] = 0;
        $response["message"] = "Please fill in the login details!";
        die(json_encode($response));
    }

    $query = "SELECT  email, password, position FROM user   WHERE   email = :email ";

    $query_params = array(':email' => $_POST['username'],);

    try {
        $stmt   = $db->prepare($query);
        $result = $stmt->execute($query_params);
    }
    catch (PDOException $ex) {
    // For testing, you could use a die and message. 
    //die("Failed to run query: " . $ex->getMessage());

    //or just use this use this one to product JSON data:
        $response["success"] = 0;
        $response["message"] = "Database Error1. Please Try Again!";
        die(json_encode($response));

    }

    //This will be the variable to determine whether or not the user's information is correct.
    //we initialize it as false.
    $validated_info = false;
    $login_ok = false;

    //fetching all the rows from the query
    $row = $stmt->fetch();
    if ($row) {
        //if we encrypted the password, we would unencrypt it here, but in our case we just
        //compare the two passwords
        if ($_POST['password'] === $row['password']) {
            $login_ok = true;       
        }

    // If the user logged in successfully, then we send them to the private members-only page 
    // Otherwise, we display a login failed message and show the login form again 
        if ($login_ok) {
            $response["success"] = 1;
            $response["message"] = "Login Successful!";
            $response["posts"]   = array();

                foreach ($row as $rerow) {
                $row = array(
                $post["position"] = $rerow["position"]
                            );

                array_push($response["posts"], $post);
                }

                die(json_encode($response));
        } 
        else {
            $response["success"] = 0;
            $response["message"] = "Invalid Credentials!";
            die(json_encode($response));
        }

    } 
}   
else {
    ?>
    <h1>Login</h1> 
    <form action="login.php" method="post"> 
        Username:<br /> 
        <input type="text" name="username" placeholder="username" /> 
        <br /><br /> 
        Password:<br /> 
        <input type="password" name="password" placeholder="password" value="" /> 
        <br /><br /> 
        <input type="submit" value="Login" /> 
    </form> 
    <a href="register.php">Register</a>
    <?php
}
?> 

应该是

            $row = array(
            $post["position"] => $rerow["position"]
                        );

其实

        foreach ($row as $rerow) {
            $row = array(
                $post["position"] = $rerow["position"]
            );
            array_push($response["posts"], $post);
        }

也许你想做些别的事：

do {
    $post = $row["position"]
    array_push($response["posts"], $post);
} while ($row = $stmt->fetch());

这会将字段“position”添加到posts中，并继续获取其他记录。
第57行：
$post[“position”]=$rerow[“position”]
数组的键/值对是使用
=>
设置的，而不仅仅是
=
这并不能解决问题，另外还有一个错误是
注意：在第57行的C:\xampp\htdocs\PMSS\login.php中使用了未定义的常量位置-假定的“位置”
上一个
非法字符串偏移量
错误仍在显示？是
非法字符串偏移量
仍然存在我同意你的怀疑。如果OP正在循环
$row
，并且它有多个元素，那么循环不会在一次迭代后停止，因为他们在第一次迭代中将
$row
设置为一个新数组？实际上，我试图做的是，当我使用电子邮件和密码登录时，一旦它与登录信息匹配，之后，我需要检索用户表的用户位置。同时验证用户的位置并确定Login.java将引导用户进入哪个主菜单。因为现在我使用PHP和by json数据将数据传递给我的移动应用程序的Login.java。@user3096526添加了我对您意图的解释。@JoopEggen但是如果我有几个帖子，比如$post=$row[“state”]，$post=$row[“city”]等等，然后我只需在do{and array_push（$response[“posts”]，$post）？
do {
    $post = $row["position"]
    array_push($response["posts"], $post);
} while ($row = $stmt->fetch());