Php 根据票据创建日期定义到期日期

我正在构建SLA KPI。 SLA基于票证类型和优先级，每种类型和优先级都有一个到期日

问题是，我只在创建了字段，没有这个截止日期，所以我需要计算它，如上所述，使用参数优先级和类型来定义正确的日期

但我真正的问题是，如何在PHP上计算它，考虑到工作日和工作时间，周一到周五，8:00到18:00 比如说

票证创建时间为2019-06-04 08:00:00，截止时间为16小时。

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因此，在挖掘了大量的答案之后，我找到了一个解决问题的函数

    function addRollover($givenDate, $addtime, $dayStart, $dayEnd, $weekDaysOnly) {

    //Break the working day start and end times into hours, minuets
    $dayStart = explode(',', $dayStart);
    $dayEnd = explode(',', $dayEnd);

    //Create required datetime objects and hours interval
    $datetime = new DateTime($givenDate);

    $endofday = clone $datetime;
    $endofday->setTime($dayEnd[0], $dayEnd[1]); //set end of working day time


    $interval = 'PT'.$addtime.'H';
    //Add hours onto initial given date
    $datetime->add(new DateInterval($interval));

    //if initial date + hours is after the end of working day

    if($datetime > $endofday)
    {
        //get the difference between the initial date + interval and the end of working day in seconds
        $seconds = $datetime->getTimestamp()- $endofday->getTimestamp();

        //Loop to next day
        while(true)
        {
            $endofday->add(new DateInterval('PT24H'));//Loop to next day by adding 24hrs
            $nextDay = $endofday->setTime($dayStart[0], $dayStart[1]);//Set day to working day start time
            //If the next day is on a weekend and the week day only param is true continue to add days
            if(in_array($nextDay->format('l'), array('Sunday','Saturday')) && $weekDaysOnly)
            {
                continue;
            }
            else //If not a weekend
            {
                $tmpDate = clone $nextDay;
                $tmpDate->setTime($dayEnd[0], $dayEnd[1]);//clone the next day and set time to working day end time
                $nextDay->add(new DateInterval('PT'.$seconds.'S')); //add the seconds onto the next day
                //if the next day time is later than the end of the working day continue loop
                if($nextDay > $tmpDate)
                {
                    $seconds = $nextDay->getTimestamp()-$tmpDate->getTimestamp();
                    $endofday = clone $tmpDate;
                    $endofday->setTime($dayStart[0], $dayStart[1]);

                }
                else //else return the new date.
                {
                    return $endofday;


                }
            }
        }
    }

    return $datetime;
}

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谢谢大家。

，你说得对，我忘了提到午餐时间了。谢谢，我会读它的可能副本。不，不是，我读过那篇文章，但我也需要计算时间，我不知道怎么做。我来这里寻求帮助，至少是想知道在哪里寻找正确的道路。谢谢