Php mysqli_事务不工作或我理解错误

MYphpmysqli事务的代码是

<?php

/*db connection*/

$conn = mysqli_connect("localhost", "root", "", "test");

mysqli_autocommit($conn, FALSE);

$insert1 = mysqli_query($conn, "INSERT INTO user(name,age,gender) VALUES('DEEPU', 24, 'male')");

$insert2 = mysqli_query($conn, "INSERT INTO user(name,age,gender2) VALUES('ANIL', 25, 'male')");

mysqli_commit($conn);

mysqli_close($conn);

?>

它将进入

交易前

状态

注意：我正在使用

innoDB

引擎

我需要什么

If both query is correct: data should insert.

If one is correct and other is wrong: no data will insert.

---

Pease help…谢谢。

mysqli\u查询

成功查询时返回true。如果两个查询都成功，您可以使用它提交，如果其中一个查询失败，您可以使用它回滚

$conn = mysqli_connect("localhost", "root", "", "test");

mysqli_autocommit($conn, FALSE);

$query1 = "INSERT INTO user(name,age,gender) VALUES('DEEPU', 24, 'male')";    
$query2 = "INSERT INTO user(name,age,gender2) VALUES('ANIL', 25, 'male')";

if(mysqli_query($conn, $query1) && mysqli_query($conn, $query2))
{
     mysqli_commit($conn);
}else
{
     mysqli_rollback($conn);
}

mysqli_close($conn);

$conn = mysqli_connect("localhost", "root", "", "test");

mysqli_autocommit($conn, FALSE);

$query1 = "INSERT INTO user(name,age,gender) VALUES('DEEPU', 24, 'male')";    
$query2 = "INSERT INTO user(name,age,gender2) VALUES('ANIL', 25, 'male')";

if(mysqli_query($conn, $query1) && mysqli_query($conn, $query2))
{
     mysqli_commit($conn);
}else
{
     mysqli_rollback($conn);
}

mysqli_close($conn);