Php 安卓：Can'；不要将数据发送到MYSQL。导致崩溃

我正在尝试构建一个android应用程序，它通过用户输入填充一个数据库表，但该应用程序不会填充所有列，有些列会故意为空。无论何时我试图提交它都会崩溃我做错了什么

我尝试过一个接一个地消除java类和php中的变量，但没有成功

类别代码

// Progress Dialog
private ProgressDialog pDialog;

JSONParser jsonParser = new JSONParser();
EditText start;
EditText end;
EditText reasonfield;
Spinner spinner;
// url to create new product
private static String url_create_contact = "http://10.0.3.2/sunshie-ems/create_contact.php";

// JSON Node names
private static final String TAG_SUCCESS = "success";

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.leave);

    // Edit Text
    start = (EditText) findViewById(R.id.start);
    end = (EditText) findViewById(R.id.end);
    reasonfield = (EditText) findViewById(R.id.reasonfield);
    Spinner mySpinner=(Spinner) findViewById(R.id.spinner);

    // Create button
    Button submit = (Button) findViewById(R.id.submit);

    // button click event
    submit.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View view) {
            // creating new product in background thread
            new CreateNewProduct().execute();
        }
    });
}

/**
 * Background Async Task to Create new product
 * */
class CreateNewProduct extends AsyncTask<String, String, String> {

    /**
     * Before starting background thread Show Progress Dialog
     * */
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        pDialog = new ProgressDialog(Leave.this);
        pDialog.setMessage("Creating Leave..");
        pDialog.setIndeterminate(false);
        pDialog.setCancelable(true);
        pDialog.show();
    }

    /**
     * Creating product
     * */
    protected String doInBackground(String... args) {
        String name = start.getText().toString();
        String number = end.getText().toString();
        String about = reasonfield.getText().toString();
        String leave = spinner.getSelectedItem().toString();


        // Building Parameters
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        params.add(new BasicNameValuePair("name", name));
        params.add(new BasicNameValuePair("number", number));
        params.add(new BasicNameValuePair("about", about));
        params.add(new BasicNameValuePair("leave", leave));
        // getting JSON Object
        // Note that create product url accepts POST method
        JSONObject json = jsonParser.makeHttpRequest(url_create_contact,
                "POST", params);

        // check log cat fro response
        Log.d("Create Response", json.toString());

        // check for success tag
        try {
            int success = json.getInt(TAG_SUCCESS);

            if (success == 1) {
                // successfully created product
                Toast.makeText(getApplicationContext(), "Successful", Toast.LENGTH_LONG).show();
                //Intent i = new Intent(getApplicationContext(), MainActivity.class);
                //startActivity(i);

                // closing this screen
                finish();
            } else {
                Toast.makeText(getApplicationContext(), "Failed", Toast.LENGTH_LONG).show();
                // failed to create product
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }

        return null;
    }

    /**
     * After completing background task Dismiss the progress dialog
     * **/
    protected void onPostExecute(String file_url) {
        // dismiss the dialog once done

        pDialog.dismiss();
    }

}
}

PHP“创建联系人”

---

您正在将微调器设置为

mySpinner

，并从

spinner

获取值，这会导致

NullPointerException

，因此请更改

  Spinner mySpinner=(Spinner) findViewById(R.id.spinner)

到

同时从查询中删除额外报价，即更改

$result = mysql_query("INSERT INTO leavelist(leavetype, date, start, end, reason) VALUES(''$leavetype', '$date', '$start', '$end', '$reason')");

到

---

由于某些原因，PHP代码不会出现D：将您的json数据上传到Hered，您是指我的json代码吗？我确信这不会导致错误，因为该应用程序还有一个登录功能，它可以很好地登录you@insert_name_here你说不工作是什么意思，更新

'$leavetype'

=>

'$leavetype'

中的logcat exceptionExtra quote，我想为我在尝试显示PHP代码时出现的额外quote道歉，因为它不久前没有显示。在检查我的代码后，它没有额外的报价

  Spinner mySpinner=(Spinner) findViewById(R.id.spinner)

  spinner=(Spinner) findViewById(R.id.spinner)

$result = mysql_query("INSERT INTO leavelist(leavetype, date, start, end, reason) VALUES(''$leavetype', '$date', '$start', '$end', '$reason')");

$result = mysql_query("INSERT INTO leavelist(leavetype, date, start, end, reason) VALUES('$leavetype', '$date', '$start', '$end', '$reason')");