Php 将txt解析为json

我有一个txt文件，看起来像：

1 - 10
2 - 20
3 - 30

{
  "item": "1",
  "value": "10"
},

{
  "item": "2",
  "value": "20"
},

{
  "item": "3",
  "value": "30"
},

我如何制作一个json数组，其外观如下：

1 - 10
2 - 20
3 - 30

{
  "item": "1",
  "value": "10"
},

{
  "item": "2",
  "value": "20"
},

{
  "item": "3",
  "value": "30"
},

---

谢谢

您需要逐行读取文本文件，并用分隔符“-”分解该行。然后创建一个可以转换为json的数组

// Open the file to read data.
$fh = fopen('student.txt','r');
// define an eampty array
$data = array();
// read data
while ($line = fgets($fh)) {
    // if the line has some data
   if(trim($line)!=''){
       // explode each line data 
       $line_data = explode('-',$line);
       // push data to array
       //array_push($data,array('item'=>trim($line_data[0]),'value'=>trim($line_data[1])));
       $data[]=array('item'=>trim($line_data[0]),'value'=>trim($line_data[1]));
   }
}
fclose($fh);
// json encode the array
echo $json_data = json_encode($data);

输出：

[{"item":"1","value":"10"},
{"item":"2","value":"20"},
{"item":"3","value":"30"}]

---

另一种方法解决方案：

您尝试过任何代码吗？您使用的是什么语言？

<?php

// the list in the txt file 
$str = "1 - 10
        2 - 20
        3 - 30";


$so = explode(" ", $str);



$cleanedvalues = array();

foreach ($so as $key => $value) {
    if ($value != "") {
        $cleanedvalues[] = $value;
    }
}


$arrval = array();

foreach ($cleanedvalues as $key => $value) {
    if ($value == "-") {

    } else {
        $arrval[] = $value;
    }
}



$tab_keys   = array();
$tab_values = array();
foreach ($arrval as $key => $value) {
    if ($key % 2 == 0) {
        $tab_keys[] = $value;
    } else {
        $tab_values[] = $value;
    }

}

// add the item and value data 
$lan = array();
for ($i = 0; $i < sizeof($tab_keys); $i++) {
    $lan[] = array(
        'item' => trim($tab_keys[$i]),
        'value' => trim($tab_values[$i])
    );
}

// the final result 
echo json_encode($lan);
?>