Php 两份申请表格

Php 两份申请表格,php,forms,submission,Php,Forms,Submission,我有PHP代码,它为每个列表项创建一个带有单选按钮的列表 $result = mysql_query("SELECT * FROM attitudes WHERE x_axis = '$famID'",$db); $rowcheck = mysql_num_rows($result); while ($row_user = mysql_fetch_assoc($result)) foreach ($row_user as $col=>$val) { if ($col !=

我有PHP代码,它为每个列表项创建一个带有单选按钮的列表

$result = mysql_query("SELECT * FROM attitudes WHERE x_axis = '$famID'",$db);
$rowcheck = mysql_num_rows($result);
while ($row_user = mysql_fetch_assoc($result))   

foreach ($row_user as $col=>$val) {
    if ($col != $famID && $col != 'x_axis') {
        list($famname) = mysql_fetch_row(mysql_query("SELECT familyname FROM families WHERE families_ID='$col'",$db));
        echo "col $col famname $famname is val $val.";
        echo "<input type = \"radio\" name = \"whichfam\" value = \"$col\" />";
        echo "</br>";

    }
}
$result=mysql\u查询(“从x\u轴=“$famID'”,$db中选择*);
$rowcheck=mysql\u num\u行($result);
while($row\u user=mysql\u fetch\u assoc($result))
foreach($col=>$val的行\用户){
如果($col!=$famID&$col!='x_轴'){
list($famname)=mysql_fetch_行(mysql_查询(“从族中选择族名,其中族ID='$col',$db));
echo“col$col famname$famname是val$val.”;
回声“;
回声“
”; } }
然后,我在底部有一个提交按钮(以及整个事情的表单标签)

我想要两份可能的意见书。此代码旨在让玩家提高或降低值。他们单击其中一个单选按钮,然后选择“升高”或“降低”。然后,它应该发布到后端并执行代码来提高或降低该值。我知道如何在jquery中实现这一点,但我不知道如何在PHP中使用两个提交按钮

我该怎么做


(具体地说,我如何使两个提交按钮工作,后端代码应该相对简单,$\u POST或其他任何东西)

这就是您想要的吗

<button type="submit" name="submit1" value="submit1">submit1</button>
<button type="submit" name="submit2" value="submit2">submit2</button>

这就是你要找的吗

<button type="submit" name="submit1" value="submit1">submit1</button>
<button type="submit" name="submit2" value="submit2">submit2</button>