Php PSR-4自动加载选项没有在我的项目中加载类?
当我尝试使用psr-4自动加载选项加载我的类时,我得到以下错误“致命错误:未捕获错误:在C:\xampp\htdocs\gacho\App\Core\Application.php:17堆栈跟踪:#0 C:\xampp\htdocs\gacho\public\index.php(16):App\Core\Application->u construct()#1{main}在第17行的C:\xampp\htdocs\gacho\App\Core\Application.php中抛出“这是我的代码结构和代码: 代码结构:Php PSR-4自动加载选项没有在我的项目中加载类?,php,oop,autoload,psr-4,Php,Oop,Autoload,Psr 4,当我尝试使用psr-4自动加载选项加载我的类时,我得到以下错误“致命错误:未捕获错误:在C:\xampp\htdocs\gacho\App\Core\Application.php:17堆栈跟踪:#0 C:\xampp\htdocs\gacho\public\index.php(16):App\Core\Application->u construct()#1{main}在第17行的C:\xampp\htdocs\gacho\App\Core\Application.php中抛出“这是我的代码结
|gacho
|- App
|- Controller
|- HomeController.php
|- Core
|- Application.php
|- Model
|- View
|-public
|- .htaccess
|- index.php
|-vendor
|- composer
|- autoload_classmap.php
|- autoload.php
|-composer.json
index.php:
<?php
use App\Core\Application;
define('ROOT', dirname(__DIR__) . DIRECTORY_SEPARATOR);
define('APP', ROOT . 'App' . DIRECTORY_SEPARATOR);
define('CONTROLLER', ROOT . 'App' . DIRECTORY_SEPARATOR . 'Controller' .
DIRECTORY_SEPARATOR);
define('VIEW', ROOT . 'App' . DIRECTORY_SEPARATOR . 'View' .
DIRECTORY_SEPARATOR);
define('MODEL', ROOT . 'App' . DIRECTORY_SEPARATOR . 'Model' .
DIRECTORY_SEPARATOR);
define('CORE', ROOT . 'App' . DIRECTORY_SEPARATOR . 'Core' .
DIRECTORY_SEPARATOR);
$modules = [ROOT, APP, CORE, CONTROLLER];
require_once __DIR__ . '\..\vendor\autoload.php';
$app = new Application();
Application.php:
<?php
namespace App\Core;
use App\Core\Controller;
use App\Controller\HomeController;
class Application
{
protected $controller = 'HomeController';
protected $action = 'index';
protected $params = [];
public function __construct()
{
$this->prepareURL();
if (file_exists(CONTROLLER. $this->controller . '.php')) {
$this->controller = new $this->controller;
if (method_exists($this->controller, $this->action)) {
call_user_func_array([$this->controller, $this->action], $this->params);
}
}
}
protected function prepareURL()
{
$request = trim($_SERVER['REQUEST_URI'], '/');
if (!empty($request)) {
$url = explode('/', $request);
$this->controller = isset($url[0]) ? $url[0].'Controller' : 'HomeController';
$this->action = isset($url[1]) ? $url[1] : 'index';
unset($url[0], $url[1]);
$this->params = !empty($url) ? array_values($url) : [];
}
}
}
FQCN是App\Core\Application
,路径是App\Core\Application.php
。使用PSR-4,它将尝试从App\Core\Application.php
加载,但该路径不存在(至少在区分大小写的文件系统中不存在)
最好的选择是更改目录结构以匹配名称空间。它们需要精确匹配,包括大小写。尝试运行此命令:编写器更新
请提供一个。此外,还应验证重现行为所需的步骤是否有效。特别要注意的是,自动装弹机的生成方式会对。。。顺便说一句:根据广泛接受的说法,你的类名homeController
是无效的。考虑不要打破这些惯例,它会使事情变得更容易。看@ ReVo我做了一切,从那个帖子,它仍然不会工作。相同的错误。它正在MS Windows上运行,从一条错误消息中可以看出。看起来是这样的。不过,路径和命名空间并不完全匹配,这就是问题所在。@Arjan它在Windows 7上运行。我更改了每个目录以匹配名称空间,并点击composer dumpautoload,我仍然得到几乎相同的错误,只是更改了小写字母的致命错误:未捕获错误:在C:\xampp\htdocs\gacho\App\Core\Application.php中找不到类“HomeController”。php:17堆栈跟踪:#0 C:\xampp\htdocs\gacho\public\index.php(16):App\Core\Application->uuu construct()#1{main}在C:\xampp\htdocs\gacho\App\Core\Application.php的第17行“当我在Application.php中从受保护的$controller中删除名称HomeController时,如果有帮助,我不会得到错误,只是空白页。
<?php
namespace App\Core;
use App\Core\Controller;
use App\Controller\HomeController;
class Application
{
protected $controller = 'HomeController';
protected $action = 'index';
protected $params = [];
public function __construct()
{
$this->prepareURL();
if (file_exists(CONTROLLER. $this->controller . '.php')) {
$this->controller = new $this->controller;
if (method_exists($this->controller, $this->action)) {
call_user_func_array([$this->controller, $this->action], $this->params);
}
}
}
protected function prepareURL()
{
$request = trim($_SERVER['REQUEST_URI'], '/');
if (!empty($request)) {
$url = explode('/', $request);
$this->controller = isset($url[0]) ? $url[0].'Controller' : 'HomeController';
$this->action = isset($url[1]) ? $url[1] : 'index';
unset($url[0], $url[1]);
$this->params = !empty($url) ? array_values($url) : [];
}
}
}
<?php
namespace App\Controller;
use App\Core\Controller;
class HomeController extends Controller
{
public function index($id= '', $name='')
{
$this->view('home\index', [
'name' => $name,
'id' => $id
]);
$this->view->page_title = 'Home Page';
$this->view->render();
}
public function users()
{
$this->view('home\users', []);
$this->view->page_title = 'Users';
$this->view->render();
}
}