Php 我似乎无法将数据正确地输入JSON

您好，我花了相当多的时间试图让我的数据在JSON中显示为以下示例：

var json = {
    "id": "347_0",
    "name": "Nine Inch Nails",
    "children": [{
        "id": "126510_1",
        "name": "Jerome Dillon",
        "data": {
            "band": "Nine Inch Nails",
            "relation": "member of band"
        },
        "children": [{
            "id": "52163_2",
            "name": "Howlin' Maggie",
            "data": {
                "band": "Jerome Dillon",
                "relation": "member of band"
            },
            "children": []
        }, {
            "id": "324134_3",
            "name": "nearLY",
            "data": {
                "band": "Jerome Dillon",
                "relation": "member of band"
            },
            "children": []
        }]
    }, {
        "id": "173871_4",
        "name": "Charlie Clouser",
        "data": {
            "band": "Nine Inch Nails",
            "relation": "member of band"
        },
        "children": []
    }, {
        "id": "235952_5",
        "name": "James Woolley",
        "data": {
            "band": "Nine Inch Nails",
            "relation": "member of band"
        },
        "children": []
    },

我正在使用json_encode函数，我知道如何将数据转换成json，但我似乎无法创建任何输出上述json格式的内容……例如，我使用以下代码：

    foreach($relations as $rel){
        $data[$id]["relationTo"] = $rel["name"];
        $data[$id]["relation"] = $rel["relation"];
        $id = $id + 1;
    }
    $id = 0;
    foreach($relations as $rel){
        $children[$id]["id"] = $id+1;
        $children[$id]["name"] = $rel["sname"];
        $children[$id]["data"] = $data[$id];
        $id = $id + 1;
    }
    $relationsArray["id"] = 0;
    $relationsArray["name"] = $rel["name"];
    $relationsArray["children"] = $children;

    $json_content =  json_encode($relationsArray);

这就产生了：

"id":0,
"name":"Al",
"children":[
  {
     "id":1,
     "name":"Brandon",
     "data":{
        "relationTo":"Albaraa",
        "relation":"Friend"
     },
     "children":[

     ]
  },
  {
     "id":2,
     "name":"Shen",
     "data":{
        "relationTo":"Albaraa",
        "relation":"Friend"
     },
     "children":[

     ]
  },
  {
     "id":3,
     "name":"Dan",
     "data":{
        "relationTo":"Albaraa",
        "relation":"Professor"
     },
     "children":[

     ]
  },
  {
     "id":4,
     "name":"Bob",
     "data":{
        "relationTo":"Albaraa",
        "relation":"Boss"
     },
     "children":[

     ]
  },
  {
     "id":5,
     "name":"Al",
     "data":{
        "relationTo":"Albaraa",
        "relation":"God Father"
     },
     "children":[

     ]
  },
  {
     "id":6,
     "name":"Albaraa",
     "data":{
        "relationTo":"Shen",
        "relation":"Friend"
     },
     "children":[

     ]
  },
  {
     "id":7,
     "name":"Brandon",
     "data":{
        "relationTo":"Shen",
        "relation":"Friend"
     },
     "children":[

     ]
  },
  {
     "id":8,
     "name":"Dan",
     "data":{
        "relationTo":"Shen",
        "relation":"Professor"
     },
     "children":[

     ]
  },
  {
     "id":9,
     "name":"Albaraa",
     "data":{
        "relationTo":"Al",
        "relation":"God Son"
     },
     "children":[

     ]
  },
  {
     "id":10,
     "name":"Bob",
     "data":{
        "relationTo":"Al",
        "relation":"Best Friends"
     },
     "children":[

     ]
  }
 ]
}

等等…但是我不能得到你上面看到的孩子们的孩子们

任何帮助都会令人惊讶的谢谢

编辑：

---

在foreach循环之前为$children赋值之前，您没有声明$children。因此，像这样声明数组并将代码更改为

$children = array();
$id = 0;
    foreach($relations as $rel){
        $children[$id]["id"] = $id+1;
        $children[$id]["name"] = $rel["sname"];
        $children[$id]["data"] = $data[$id];
        $id = $id + 1;
    }

---

在第一个字符串中执行

json\u解码

。然后对其进行反向工程。然后，您将获得数组格式并相应地创建新数组。在发布的代码中，您从不分配

$children[$id][“children”]

，因此它不应该出现在json中（它作为空数组存在）。发布所有操作

$children

数组的代码。我通过创建一个类添加了另一个尝试的编辑。。。对于我的其他代码，我刚刚开始一个新的尝试，我不确定如何显示其他$children中的更多$children@itachi我正在尝试json_解码到目前为止，我似乎无法让这个函数工作，但我会继续工作，谢谢！实际上，我声明很抱歉，我没有在上面的代码中包含这一点，但我显示了我得到的输出，并且我能够将子项输入到第一个创建的id/名称中，但我无法获得下一组子项的子项，以此类推。。。

$children = array();
$id = 0;
    foreach($relations as $rel){
        $children[$id]["id"] = $id+1;
        $children[$id]["name"] = $rel["sname"];
        $children[$id]["data"] = $data[$id];
        $id = $id + 1;
    }