Php 如何访问iOS作为参数发送的参数
我正在从iOS端API发送数据,如Php 如何访问iOS作为参数发送的参数,php,ios,Php,Ios,我正在从iOS端API发送数据,如 { "broker_name" : " test 2", "concession" : 2, "doller_rate" : 70, "due_day" : 30, "party_name" : "Test", "payment_amount" : "274.4", "payment_date" : "02 May 2016", "rate" : 0, "sale_date" :
{
"broker_name" : " test 2",
"concession" : 2,
"doller_rate" : 70,
"due_day" : 30,
"party_name" : "Test",
"payment_amount" : "274.4",
"payment_date" : "02 May 2016",
"rate" : 0,
"sale_date" : "02 April 2016",
"serial_number" : "Test 1",
"transection_type" : 1,
"user_id" : 2,
"weight" : [{
"carat_rate" : 2,
"carat_weight" : 2,
"sub_serial_Note" : "d",
"total" : "4.0",
},
{
"carat_rate" : 4,
"carat_weight" : 4,
"sub_serial_Note" : "k",
"total" : "16.0"
}]
}
如何在PHP中访问此参数,并使用字典访问正确的数组 您希望在varible上获得json
$json_get = $_REQUEST['yoursenddata'];
然后将这些数据解码到数组中
$json_array=json_decode($json);
print_r($json_array);
$broker = $json_array['broker_name'];
其他人也一样。为什么不改为发送JSON?然后你可以使用
json\u decode
@Gordon这是iPhone中的json我想访问权重,我得到了所有参数,但我无法访问权重。显示的数据不是json,因此json\u decode不会对其进行解码