Php 更新数据库集。。。用0或1填充一个特定的VARCHAR，而不管我设置的值是多少

我正在通过php mysqli

$con->query（$sql）运行以下查询

PHP代码：

$sql = 'UPDATE registrations SET '.$update_columns_list.' WHERE registrationkey = "'.$registration['RegistrationKey'].'"';
echo "RESULT: ".$result = $con->query($sql);

在上述示例中，
$sql
的值：

UPDATE registrations SET referenceid = "4469731" and action = "newregistration" and status = "newregistration" and registrationdatetimegmt = "1363371386" and billingmonth = "2013-03" and accessexpirationdatetimegmt = "1373957999" and returnurl = "https://api.mywebsite.com/login.aspx?siteid=209" and lastmodifieddatetimegmt = "1363371398" and studentkey = "12345-67890-12345-67890" and firstname = "amanda" and lastname = "hemingway" and email = "amandamhemingway@trashymail.com" and phonenumber = "111-111-1111" and city = "city" and state = "ca" and postalcode = "90210" and country = "us" and coursecode = "ABC-406" and coursetitle = "example course title" and courseproductcode = "t3310" WHERE registrationkey = "12345-67890-12345-67890"

运行此查询时，一切似乎都正常（我收到一条“成功”消息，受影响的行数与预期的一样）。但是，当我通过phpMyAdmin查看数据库中受影响的行时，我会在“referenceid”列中不断找到1或0值。没有影响此表或数据库的其他脚本。我无法确定它何时放置0而不是1的任何模式

referenceid
和
keyid
字段都是
VARCHAR（100）
。
您正在执行的update语句执行布尔运算。我不喜欢mysql中的这种行为

当前update语句如下所示：

UPDATE tableName SET col1 = 2 AND col2 = 3

而
MySQL
server不会抛出任何异常，因为语法是允许的，它将其读取为：

UPDATE tableName SET col1 = (2 AND (col2 = 3))

如果要更新多个列，请使用
，
将列与
分开

UPDATE registrations 
SET    referenceid = "4469731",
       action = "newregistration", .....

正在执行的update语句执行布尔运算。我不喜欢mysql中的这种行为

当前update语句如下所示：

UPDATE tableName SET col1 = 2 AND col2 = 3

而
MySQL
server不会抛出任何异常，因为语法是允许的，它将其读取为：

UPDATE tableName SET col1 = (2 AND (col2 = 3))

如果要更新多个列，请使用
，
将列与
分开

UPDATE registrations 
SET    referenceid = "4469731",
       action = "newregistration", .....

更新时，不使用and而不是逗号添加列，因此更新应如下所示：

UPDATE registrations 
 SET referenceid = "4469731",
     action = "newregistration",
     status = "newregistration",
     registrationdatetimegmt = "1363371386",
     billingmonth = "2013-03",
     accessexpirationdatetimegmt = "1373957999",
     returnurl = "https://api.mywebsite.com/login.aspx?siteid=209",
     lastmodifieddatetimegmt = "1363371398",
     studentkey = "12345-67890-12345-67890",
     firstname = "amanda",
     lastname = "hemingway",
     email = "amandamhemingway@trashymail.com",
     phonenumber = "111-111-1111",
     city = "city",
     state = "ca",
     postalcode = "90210",
     country = "us",
     coursecode = "ABC-406",
     coursetitle = "example course title",
     courseproductcode = "t3310"
 WHERE registrationkey = "12345-67890-12345-67890"

更新时，不使用and而不是逗号添加列，因此更新应如下所示：

UPDATE registrations 
 SET referenceid = "4469731",
     action = "newregistration",
     status = "newregistration",
     registrationdatetimegmt = "1363371386",
     billingmonth = "2013-03",
     accessexpirationdatetimegmt = "1373957999",
     returnurl = "https://api.mywebsite.com/login.aspx?siteid=209",
     lastmodifieddatetimegmt = "1363371398",
     studentkey = "12345-67890-12345-67890",
     firstname = "amanda",
     lastname = "hemingway",
     email = "amandamhemingway@trashymail.com",
     phonenumber = "111-111-1111",
     city = "city",
     state = "ca",
     postalcode = "90210",
     country = "us",
     coursecode = "ABC-406",
     coursetitle = "example course title",
     courseproductcode = "t3310"
 WHERE registrationkey = "12345-67890-12345-67890"

这是您正在执行的完整update语句吗？包含查询的php代码是什么？请尝试逗号而不是
，并将
和
替换为
，
谢谢，Waygood。这解决了问题。在回答J W下面的回答后，我看到了您的评论。这是您正在执行的完整更新语句吗？包含查询的php代码是什么？请尝试逗号而不是
，并用
替换
和
s，
谢谢，Waygood。这解决了问题。我在回复J W下面的答案后看到了你的评论。谢谢！导致我原来问题的逻辑缺陷现在清楚多了。谢谢！导致我最初问题的逻辑缺陷现在更清楚了。