Php 多维数组构造
我从SQL结果中得到了这种类型的数组Php 多维数组构造,php,multidimensional-array,Php,Multidimensional Array,我从SQL结果中得到了这种类型的数组 +-------------+---------------+-----------------+----------------+ | business_id | business_name | business_branch | branch_contact | +-------------+---------------+-----------------+----------------+ | 1 | ABC
+-------------+---------------+-----------------+----------------+
| business_id | business_name | business_branch | branch_contact |
+-------------+---------------+-----------------+----------------+
| 1 | ABC | 1 | 1111111111 |
+-------------+---------------+-----------------+----------------+
| 1 | ABC | 2 | 2222222222 |
+-------------+---------------+-----------------+----------------+
| 1 | ABC | 3 | 3333333333 |
+-------------+---------------+-----------------+----------------+
| 1 | ABC | 4 | 4444444444 |
+-------------+---------------+-----------------+----------------+
| 2 | XYZ | 1 | 5555555555 |
+-------------+---------------+-----------------+----------------+
| 2 | XYZ | 2 | 6666666666 |
+-------------+---------------+-----------------+----------------+
一开始,我想为每个分支机构和业务做一个单独的数据库查询。但我知道这是一个糟糕的做法
我想构建如下结果
[
{
business_id : 1,
business_name : ABC,
branches : [
{
branch_id : 1,
branch_contact : 1111111111
},
{
branch_id : 2,
branch_contact : 2222222222
},
...
},
{
business_id : 1,
business_name : ABC,
branches : [
{
...
}
}
]
}
我试图构建的当前函数没有提供必要的输出。如下所示
$previousBusiness = '';
$previousBranch = '';
$businessAndBranchArray = [];
$businessArray = [];
$branchArray = [];
foreach ($results as $result) {
$currentBranch = [];
$currentBusiness = [];
$currentMerchant = [];
if($result['business_id'] != $previousBusiness && $result['branch_id'] != $previousBranch){
if($previousBranch != '' && $previousBusiness != ''){
$businessArray['business_id'] = $result['business_id'];
$businessArray['business_id'] = $result['business_name'];
$branchArray['branch_id'] = $result['branch_id'];
$branchArray['branch_contact'] = $result['branch_contact'];
} else {
$businessArray['business_id'] = $result['business_id'];
$businessArray['business_id'] = $result['business_name'];
$branchArray['branch_id'] = $result['branch_id'];
$branchArray['branch_contact'] = $result['branch_contact'];
}
$previousBusiness = $result['business_id'];
} else {
$branchArray['branch_id'] = $result['branch_id'];
$branchArray['branch_contact'] = $result['branch_contact'];
}
}
无需跟踪以前的项目等,只需将ID用作数组键,以便检查它是否存在。如果您不想在最终输出中使用它,请使用
array\u values()
删除键:
<?php
$results = [
["business_id" => 1, "business_name" => "ABC", "business_branch" => 1, "branch_contact" => "1111111111"],
["business_id" => 1, "business_name" => "ABC", "business_branch" => 2, "branch_contact" => "2222222222"],
["business_id" => 1, "business_name" => "ABC", "business_branch" => 3, "branch_contact" => "3333333333"],
["business_id" => 1, "business_name" => "ABC", "business_branch" => 4, "branch_contact" => "4444444444"],
["business_id" => 2, "business_name" => "XYZ", "business_branch" => 1, "branch_contact" => "5555555555"],
["business_id" => 2, "business_name" => "XYZ", "business_branch" => 2, "branch_contact" => "6666666666"],
];
$output = [];
foreach ($results as $result) {
if (empty($output[$result["business_id"]])) {
$output[$result["business_id"]] = [
"business_id" => $result["business_id"],
"business_name" => $result["business_name"],
"branches" => [],
];
}
$output[$result["business_id"]]["branches"][] = [
"branch_id" => $result["business_branch"],
"branch_contact" => $result["branch_contact"],
];
}
echo json_encode(array_values($output), true);
工作得很有魅力。谢谢你的帮助:)我能知道什么是最好的做法吗。上述矿山或关键价值评估方法(考虑建筑剩余API时)
[{"business_id":1,"business_name":"ABC","branches":[{"branch_id":1,"branch_contact":"1111111111"},{"branch_id":2,"branch_contact":"2222222222"},{"branch_id":3,"branch_contact":"3333333333"},{"branch_id":4,"branch_contact":"4444444444"}]},{"business_id":2,"business_name":"XYZ","branches":[{"branch_id":1,"branch_contact":"5555555555"},{"branch_id":2,"branch_contact":"6666666666"}]}]